All categories

3 years ago

What is a Geometric series

Mathematics

1 answer:

IRISSAK [1]3 years ago

5 0

Answer:

Step-by-step explanation:

Series having the constant ratio between any term and its preceding one.

You might be interested in

Quick easy one to do!! 15pts

Lyrx [107]

Answer:

Step-by-step explanation:

90-56=34

3 0

2 years ago

Read 2 more answers

What is the property to this problem ab+ac=(b+c)a

ryzh [129]

Answer:

Distributive Property of Multiplication

6 0

3 years ago

Read 2 more answers

14/15 divided by 7/5

Charra [1.4K]

9514 1404 393

Answer:

2/3

Step-by-step explanation:

There are a couple of different ways that division of fractions can be done.

1) "invert and multiply"

$\dfrac{14}{15}\div\dfrac{7}{5}=\dfrac{14}{15}\times\dfrac{5}{7}\\\\=\dfrac{14}{7}\times\dfrac{5}{15}=\boxed{\dfrac{2}{3}}$

2) use the numerators when the denominators are the same

$\dfrac{14}{15}\div\dfrac{7}{5}=\dfrac{14}{15}\div\dfrac{21}{15}\\\\=\dfrac{14}{21}=\boxed{\dfrac{2}{3}}$

6 0

3 years ago

An organic farm has been growing an heirloom variety of summer squash. A sample of the weights of 40 summer squash revealed that

natta225 [31]

Answer:

b. 0.0228

Step-by-step explanation:

We are given that

n=40

Mean, $\mu=402.7 g$

Standard deviation, $\sigma=8.8$ g

We have to find the probability hat the mean weight for a sample of 40 summer squash exceeds 405.5 grams.

$P(x>405.5)=P(\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}>\frac{405.5-402.7}{\frac{8.8}{\sqrt{40}}})$

$P(x>405.5)=P(Z>\frac{2.8}{\frac{8.8}{\sqrt{40}}})$

$P(x>405.5)=P(Z>2.01)$

$P(x>405.5)=1-P(Z\leq 2.01)$

$P(x>405.5)=1-0.977784$

$P(x>405.5)=0.022216$

Hence, option b is correct.

5 0

2 years ago

A factory makes 1500 cans per minute, the factory makes cans for 8 hours a day, each can is filled with 300ml of cola, how much

3241004551 [841]

1500 x 60 = the number of cans made in one hour (90,000)
90,000 x 8 = the number of cans made in 8 hours (720,000)
720,000 x 300 = 216,000,000 ml of cola

Hope this helps you out!

5 0

2 years ago