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topjm [15]
3 years ago
5

SOMEONE PLEASEEEEEEEE!!!!!!11

Mathematics
2 answers:
Amanda [17]3 years ago
8 0

Answer:

Step-by-step explanation:

Unit rate = (420 miles)/(12 gallons) = (420/12 miles)/gallon = (35 miles)/gallon

:::::

Fuel consumption = (number of miles) × (1 gallon)/(35 miles)

:::::

287 miles × (1 gallon)/(35 miles) = 8.2 gallons

bazaltina [42]3 years ago
6 0

Answer:

sorry i only know the answer of c

it's 8.2 gallons

Step-by-step explanation:

12 gallons = 420 miles

12 gallons = 420 miles? gallons =287 miles

420 miles ÷ 12 gallons = 35miles/gallon

420 miles ÷ 12 gallons = 35miles/gallon287 miles ÷ 35 miles/gallon = 8.2 gallons

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3 years ago
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cluponka [151]

Answer:

Answer below

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3 0
3 years ago
Help!!!
Jobisdone [24]

Answer:

In the year 2019 the number of new cars purchased will reach 15,000.

Step-by-step explanation:

t = 0 corresponds to the number of new cars purchased in 1998. If that is so, we can determine t ( time ) by making our quadratic equation here equal to 15,000 - considering that we want the year the number of cars reaches this value. t here is only the number of years to reach 15,000 cars, so we would have to add that value to 1998, to see the year that the cars will reach 15,000.

The " set up " should look like the following quadratic equation -

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20t² + 135t - 11950 = 0 - From here on let us solve using the quadratic equation formula,

t=\frac{-135+\sqrt{135^2-4\cdot \:20\left(-11950\right)}}{2\cdot \:20}:\quad \frac{-27+\sqrt{38969}}{8},

t=\frac{-135-\sqrt{135^2-4\cdot \:20\left(-11950\right)}}{2\cdot \:20}:\quad -\frac{27+\sqrt{38969}}{8} ... now as you can see we have two solutions, but time can't be negative, and hence our solution is the first one - about 21.3 years. 1998 + 21.3 = ( About ) The year 2019. Therefore, in the year 2019 the number of new cars purchased will reach 15,000.

3 0
4 years ago
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5 0
3 years ago
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Dominik [7]
I’m not sure what 1. is sorry, but I think I know what 2 and 3 are.
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3 years ago
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