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Elena-2011 [213]
4 years ago
14

Simplify (-2/3)/(-7/4)

Mathematics
1 answer:
Ket [755]4 years ago
4 0

Answer:

8/21

Step-by-step explanation:

(-2/3)/(-7/4)

When dividing, reciprocate the dividend then multiply to the divisor.

<u />

<u>Reciprocate</u>

-4/7

<u />

<u>Multiply</u>

-2/3 * -4/7

8/21

<u />

<u>Answer</u>

8/21

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3 years ago
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N+12=4 what is the process of the equation
Sunny_sXe [5.5K]

Hey there!

Here is your question -

n+12=4

In this equation, you're looking for n alone. To keep the variable alone, you have to do the opposite of what's happening to the variable.

In this equation, 12 is being added to n. The opposite of that is subtracting 12.

Subtract 12 from both sides -

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6 0
3 years ago
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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
sladkih [1.3K]

Answer:

(a) The probability that a randomly selected adult is either overweight or obese is 0.569.

(b) The probability that a randomly selected adult is neither overweight nor obese is 0.431.

Step-by-step explanation:

Let <em>A</em> = a person is over weight and <em>B</em> = a person is obese.

The information provided is:

An adult is considered overweight if the BMI ≥ 25 but BMI < 30.

An obese adult will have a BMI ≥ 30.

According to the range of BMI the events A and B are independent.

P (A) = 0.331 and P (B) = 0.357.

(a)

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P (A ∪ B) = P (A) + P (B) - P (A ∩ B)

               = P (A) + P (B) - P (A)×P (B)

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Thus, the probability that a randomly selected adult is either overweight or obese is 0.569.

(b)

Compute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(A^{c}\cup B^{c})=1-P(A\cup B)=1-0.569=0.431

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.431.

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4 years ago
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lubasha [3.4K]

Answer:

I think that it would be 5x+3.

Step-by-step explanation:

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3 years ago
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