Answer:
A, C, D
Step-by-step explanation:
Consider triangles NKL and NML. These triangles are right triangles, because
In these right triangles:
- reflexive property;
- given
Thus, triangles NKL and NML by HA postulate. Congruent triangles have congruent corresponding parts, so
![\overline{KN}\cong \overline{NM}\\ \\\overline{KL}\cong \overline{LM}\ [\text{option D is true}]](https://tex.z-dn.net/?f=%5Coverline%7BKN%7D%5Ccong%20%5Coverline%7BNM%7D%5C%5C%20%5C%5C%5Coverline%7BKL%7D%5Ccong%20%5Coverline%7BLM%7D%5C%20%5B%5Ctext%7Boption%20D%20is%20true%7D%5D)
Since
then
![7x-4=5x+12\\ \\7x-5x=12+4\\ \\2x=16\\ \\x=8\ [\text{option A is true}]\\ \\MN=KN=7\cdot 8-4=56-4=52\ [\text{option C is true}]](https://tex.z-dn.net/?f=7x-4%3D5x%2B12%5C%5C%20%5C%5C7x-5x%3D12%2B4%5C%5C%20%5C%5C2x%3D16%5C%5C%20%5C%5Cx%3D8%5C%20%5B%5Ctext%7Boption%20A%20is%20true%7D%5D%5C%5C%20%5C%5CMN%3DKN%3D7%5Ccdot%208-4%3D56-4%3D52%5C%20%5B%5Ctext%7Boption%20C%20is%20true%7D%5D)
Option B is false, because KN=52 units.
Option E is false, because LN is congruent KN, not LM
Answer:
Step-by-step explanation:
We want to find the coordinates of a certain point C(x,y) such that C divides 
and 
in the ratio m:n=3:2
The x-coordinate is given by:
The y-coordinate is given by:
AB has coordinates A(-5,9) and B(7,- 7)
We substitute the values to get:
and
Therefore C has coordinates 
The line segment that contains C is
See attachment.
1/2 fraction of whole carton was used for each serving
Pizza Express has a larger constant of proportionality than Perfect Pizzas because <u><em>1.6 > 1.5</em></u>
15/6 6/4
<em> Simplify</em>
<u>5/3 > 3/2</u>
<em>PE: 5/3 or 1.6</em>
<em>PP: 3/2 or 1.5</em>
<em />
I had this on my math test
Answer:
5 units
Step-by-step explanation:
3x + 4y = 8
4y = -3x+8
y = -3/4+2
The shortest distance between a point and a line is the perpendicular line.
Slope of the perpendicular line: 4/3 and point (-3,-2)
b = -2-(4/3)(-3) = 2
Equation of the perpendicular line: y=4/3x+2
y is equal y
4/3x+2= -3/4x+2
4/3x +3/4x = 2-2
x = 0
Plug x=0 into one of the equations to find y
y = 4/3(0) + 2
y = 2
(0,2) and (-3,-2)
Distance = sqrt [(-3-0)^2 + (-2-2)^2]
Sqrt (-3)^2+ (-4)^2
Sqrt 25 = 5
