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Anettt [7]
3 years ago
7

Does this line graph look correct?

Biology
2 answers:
motikmotik3 years ago
6 0
Yes this looks good to me
Natasha_Volkova [10]3 years ago
3 0
Looks great! Keep up the good work. :)
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Which of these structures are found in plant cells but not animal cells?
grandymaker [24]

Answer:

the answer for your question is 3 and 4

4 0
3 years ago
Identify the correct statements about Lesch-Nyhan syndrome.
Misha Larkins [42]

Answer:

a.

c.

Explanation:

Lesch Nyhan syndrome is characterized by behavioral and neurological abnormalities, and excess uric acid production in the body. It occurs in males, almost exclusively.

Changes (mutations) in the HPRT1 gene causes Lesch Nyhan syndrome and is inherited in a recessive X-linked way. Several symptoms of Lesch Nyhan syndrome are Inflammatory arthritis (gout),  involuntary movements, self-injury and kidney stones.

Hence, the correct option are a. and c.

4 0
3 years ago
In what phase of meiosis are tetrads pulled to opposite poles of the cell?
VikaD [51]

Answer:

Anaphase I

Explanation:

In anaphase I, the homologous chromosomes are pulled apart and move to opposite poles.

7 0
3 years ago
Identify the phenotypes for the offspring of a parent with the genotype IBi and a parent with the genotype IAIA. type O type A,
agasfer [191]
 <span>I is dominant, i is recessive. The A's and B's are just show which allele I is. When there is just one dominant allele, it masks the recessive in blood typing. Remember IA and IB are codominant. 

O is always ii 
A is IAi (heterozygous) or IAIA (homozygous) 
B is IBi (heterozygous) or IBIB (homozygous) 
AB is always IAIB 

Remember: You get one allele from each parent! 

1. Father must be ii, mother must be ii, so all children must be ii. 

2. Father is IAIA (the homozygous one), the mother is IBIB, so the only possibility for the children is IAIB, because you get one allele from the father and one from the mother. 

3. Father is IAi, mother is IBi, so the children can be any of the blood types, because they can have all the combinations of genotypes. 

4. Father is ii, mother is IAIB. Children can only be IAi or IBi. 

5. Father is IAIB, mother is IAIB. Children can be IAIA, IBIB, or IAIB. 

Example of Punnett square: 
3. Father is type A, heterozygous, mother is type B, heterozygous 
Father must be IAi (heterozygous) 
Mother must be IBi (heterozygous) 

_______IA ____ i 

IB____ IBIA____IBi 

i _____ IAi______ii 

Sorry, that was difficult on here, hope it's understandable. 
The father's alleles run across the top, the mother's are on the side, you follow to where they meet to find the possibilities for the children. IBIA (AB blood type), IBi (B), IAi (A), and ii (O) are the possibilities in this case. 

Hope that helps!</span>
6 0
3 years ago
The series of events in a eukaryotic cell that involve growth, replication and division
Kryger [21]
 the answer is cell cycle
7 0
4 years ago
Read 2 more answers
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