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-Dominant- [34]
3 years ago
14

What best describes Osmosis

Biology
1 answer:
Lana71 [14]3 years ago
3 0

Answer: Osmosis is the spontaneous net movement of solvent molecules through a selectively permeable membrane into a region of higher solute concentration, in the direction that tends to equalize the solute concentrations on the two sides.

Explanation:

You might be interested in
Read "What Emissions and Byproducts Are Produced from Burning Coal?" Why is the presence of mercury in water of great concern to
Degger [83]

1 - The most common emission and byproducts that are generated by burning coal are carbon dioxide, nitrogen oxides and dioxides and CCPs in genearl (coal combustion products).


2 - Mercury is a heavy liquid metal with some toxical properties. When ingested (most commonly trough water) can be fatal [for further info search Mercury Poisoning]. Something I should also point out is that most of the contaminated water sources are residual waters.



Hope it helped,


Happy homework/ study/ exam!

8 0
3 years ago
You are caring for a 6-year-old child with a swollen, painful deformity to the left forearm. as you communicate with the parents
RSB [31]
You are caring for a 6-year old child with a swollen, painful deformity to the left forearm. As you communicate with the parents of this child, you should



make sure that they remain aware of what you are doing.

3 0
3 years ago
4. A trait for snapdragon flower color is controlled by incomplete dominance.
Elena L [17]
I think it is 100 percent
7 0
4 years ago
1.
n200080 [17]

Answer:

75% of kids will be homozygous with blood type AB

25% of kids will be homozygous with blood type B

Explanation:

I'm so sorry if this is wrong this is just what I remember from 8th grade

7 0
3 years ago
“PKU” is an inherited disease caused by a recessive allele. If a woman and a man are both carriers, where P is the normal allele
user100 [1]

Answer:

Option A, 1/64

Explanation:

The genotype of a carrier female would be Pp

The genotype of a carrier male would be Pp

When these two adults are crossed , the following offspring are produced

Pp x Pp

PP, Pp, Pp, pp

Thus out of four children 3 children have normal phenotype but two are carrier.

So probability of having one normal  child (with genotype PP) is \frac{1}{4}

So the probability of  three normal children is

\frac{1}{4} *\frac{1}{4} *\frac{1}{4} \\= \frac{1}{64}

Hence, option A is correct

6 0
4 years ago
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