Answer:
that = 8 and if you want to see more you can go on
We are asked to solve for the measurement of side BC in the given right triangle ΔABC and other side measurements were also given such as AB=1 and AC = 2. Since this is a right triangle, we can use and apply the Pythagorean theorem c²= a² + b² and the solution is shown below:
c = AC
b = BC
a = AB
AC² = AB² + BC² , substitute values we have:
2² = 1² + BC²
BC² = 4-1
BC = √3
BC = 1.732
The answer for the length of BC is 1.732 units.
Answer: the graph crosses the x-axis at x = -3
<u>Step-by-step explanation:</u>
y = (x + 3)³
To find where the graph crosses the x-axis, let y = 0 and solve for x:
0 = (x + 3)³
0 = (x + 3) with a multiplicity of 3
-3 = x with a multiplicity of 3.
Since multiplicity is an ODD number, the graph CROSSES the x-axis at x = -3
<em />
<u>Graph:</u>
- Leading coefficient is POSITIVE so right side goes to +∞
- Degree of polynomial is ODD so left side goes to -∞
<em>graph is attached</em>
Answer: -27.10
Step-by-step explanation:
$46.74+ $60.86= $107.6
$107.60 -$ 134.70 =-$27.10
Answer: The required length of the segment AA' is 11 units.
Step-by-step explanation: Given that the point A(5, 11) is reflected across the X-axis.
We are to find the length of the segment AA'.
We know that
if a point (x, y) is reflected across X-axis, then its co-ordinates becomes (x, -y).
So, after reflection, the co-ordinates of the point A(5, 11) becomes A'(5, -11).
Now, we have the following distance formula :
The DISTANCE between two points P(a, b) and Q(c, d) gives the length of the segment PQ as follows :

Therefore, the length of the segment AA' is given by

Thus, the required length of the segment AA' is 11 units.