Use the formula A = p( 1 + x)^n.
A = 1831.84(1 + 0.14)^6
You can finish.
Answer:
The ratio that exist between this three elements are 25 : 19 : 13.
Step-by-step explanation:
Ratio compares one thing to another. Ratios indicate the comparison of the size of a number to another . One trick about ratio is that you can multiply or divide the ratios by same number. For example the ratio of boy to girls can be represented as 3 : 4. If you multiply the ratios by 2 you will get the ratio 6 : 8 and it still represent the same ratios of boys to girls. Ratios can be written as a fraction for example 3/4 for our example.
The cost of the unit is made up of $6.25 , $4.75 and $3.25.
$6.25 $4.75 $3.25 . Let us multiply by 100 to remove the decimals.
625 : 475 : 325 . Now let simplify the ratios by dividing through by 25.
625/25 : 475/25 : 325/25 . The simplest ratios can be written as follows
The ratios are 25 : 19 : 13.
<span>150 degrees.
Let's assume the center camera is pointed to at an angle of 0 degrees. Since it has a coverage of 60 degrees, then it will cover the angles from -30 to +30 degrees. Now we'll continue to use the +/- 30 degree coverage for the other two cameras. The second camera is aimed at 45 degrees, so it's range of coverage is 15 degrees to 75 degrees (45 +/- 30). Notice that the range from 15 degrees to 30 degrees is covered by 2 cameras. Now the 3rd camera is pointed at -45 degrees, so its coverage is from -15 degrees to -75 degrees. It also has an overlap with the 1st camera from -15 to -30 degrees.
The total coverage of all three cameras ranges from -75 degrees to 75 degrees. That means that an arc of 150 degrees in total is covered by all three cameras.</span>



now, with that template above in mind, let's see this one

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units
check the picture below