Answer:
I am pretty sure that it's C
Step-by-step explanation:
you need to do a^2+b^2=c^2
Answer:
sin-¹(10/11)
Step-by-step explanation:
The height of the building is 100 ft and the ladder is 110ft long .We can imagine this situation as a right angled ∆. For figure refer to the attachment .
- We can use ratio sine here. Let the angle of elevation be theta.
<u>In </u><u>∆</u><u> </u><u>ABC </u><u>:</u><u>-</u><u> </u>
=> sinθ = p/h
=> sinθ = 100ft / 110 ft
=> sinθ = 10/11
=> θ = sin -¹ ( 10/11) .
<h3><u>Hence </u><u>the</u><u> </u><u>angle</u><u> of</u><u> elevation</u><u> </u><u>is </u><u>sin </u><u>-</u><u>¹</u><u> </u><u>(</u><u> </u><u>1</u><u>0</u><u>/</u><u>1</u><u>1</u><u>)</u><u>. </u><u> </u></h3>
B. 250 cm3 hope this helps
Point three-hundred and nine
zero point three-hundred and nine
Answer:
15.0
Step-by-step explanation:
Let's start by looking at triangle ORQ. Since RQ is tangent to the circle, we know that angle ∠ORQ is 90°. Then, since OR is equivalent to the radius of 5, RQ is 5√3, and side OQ is clearly larger than RQ, we can identify this as a 90-60-30 degree triangle. This makes side OQ have a length of 10, and angle ∠QOR, opposite of the second largest side, has the second largest angle of 60°, leaving ∠OQR with an angle of 30°.
The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)
