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mafiozo [28]
3 years ago
6

Jake paid $40.50 per solar panel for eight panels and an additional installation fee for a total of $338.50. Jen paid $42.99 per

panel for eight panels and an additional installation fee for a total of $354.42. Find the difference between the installation fees Jake and Jen paid.
Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0

Answer: $4.00

Step-by-step explanation:

$40.50 * 8 = $324.00

$338.50 - $324.00 = $14.50

Jake’s installation fee is $14.50

$42.99 * 8 = $343.92

$354.42 - $343.92 = $10.50

Jen’s installation fee is $10.50

To find the difference between the two fees, you subtract the larger fee by the smaller fee.

$14.50 - $10.50 = $4.00

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Answer:

A. Sample Space = S = {(9, 18),(9, 19),(9, 20),(9, 21),(10, 18),(10, 19),(10, 20),(10, 21),(11, 18),(11, 19),(11, 20),(11, 21),(12, 18),(12, 19),(12, 20),(12, 21)}

B.  {(9, 18),(10, 18),(11, 18),(12, 18)}

C. {(9, 18),(9, 19),(10, 18)}

D.  {(9, 18),(9, 19),(10, 18),(11, 18),(12, 18)}

E. B(complement) ∩C =  {(9, 19)}

Step-by-step explanation:

The Sample Space would contain each element of the box A associated with each element of the box B.

A. Sample Space = S = {(9, 18),(9, 19),(9, 20),(9, 21),(10, 18),(10, 19),(10, 20),(10, 21),(11, 18),(11, 19),(11, 20),(11, 21),(12, 18),(12, 19),(12, 20),(12, 21)}

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D. The  outcomes in B∪C contains all the elements of B and C

B∪C=J∪L= {(9, 18),(9, 19),(10, 18),(11, 18),(12, 18)}

E. B complement contains those elements of the Sample Space which are not the elements of Set B.

B complement= S-B=  {(9, 19),(9, 20),(9, 21),(10, 19),(10, 20),(10, 21),(11, 19),(11, 20),(11, 21),(12, 19),(12, 20),(12, 21)}

B(complement) ∩C contains those elements of B and C which are common to both B complement and C.

B(complement) ∩C =  {(9, 19)}

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