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miv72 [106K]
3 years ago
5

Will mark as Brainliest!

Mathematics
1 answer:
Sati [7]3 years ago
6 0
I think the answer is A
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Help!!! evaluate peicewise functions
aksik [14]

Answer:

9

Step-by-step explanation:

You choose the middle one because 3<(4)<10 makes sense where as the other ones don't when you plug in 4. Then you solve the equation which is x^2-7 and then you get 16-7 which is 9.

4 0
2 years ago
What is : 65=4u+13 ????
Rus_ich [418]

Answer: 13


Step-by-step explanation:

65-13=54

54/4=13

Order of operations

6 0
3 years ago
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If f(x)= 5x + 4 and g(x) = 1/2x<br><br> find ,<br> a) fg(5)
Veseljchak [2.6K]

Answer:

f(g(5)) = 16.5

Step-by-step explanation:

To calculate f(g(5)), evaluate g(5) then substitute the value obtained into f(x)

g(5) = \frac{1}{2} × 5 = 2.5 , then

f(2.5) = 5(2.5) + 4 = 12.5 + 4 = 16.5

5 0
3 years ago
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A small combination lock on a suitcase has 55 ​wheels, each labeled with the 10 digits 0 to 9. How many 55 digit combinations ar
den301095 [7]
Suppose a_n is the number of possible combinations for a suitcase with a lock consisting of n wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for n+1 wheels, or a_{n+1} is given recursively by the formula

a_{n+1}=9a_n

starting with a_1=10 (because you can start the combination with any one of the ten available digits 0 through 9).

For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).

By substitution, you have

a_{n+1}=9a_n=9^2a_{n-1}=9^3a_{n-2}=\cdots=9^na_1=10\times9^n

This means a lock with 55 wheels will have

a_{55}=10\times9^{54}

possible combinations (a number with 53 digits).
7 0
3 years ago
Please help me with this
Triss [41]

Answer:<

Step-by-step explanation:

5 0
3 years ago
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