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4 years ago

7

An experiment consists of rolling two fair dice and adding the dots on the two sides facing up. What is the probability that the

sum of the dots is 6 or 9?

1 answer:

nata0808 [166]4 years ago

8 0

Answer:

4/15

Step-by-step explanation:

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Im confused please help

Hitman42 [59]

156/9 = 17.3

So Lina can make about 17 beaded bracelets with 156 beads.

Hope this Helps!!

3 0

3 years ago

Helpppp!! its number 6!

Ierofanga [76]

Answer:

$4.50

Step-by-step explanation:

what you do is divide $22.50 by 5 pounds

3 0

3 years ago

Triangle ABC is a right triangle.

Mashcka [7]

Answer:

x = 11.75

Step-by-step explanation:

m∠A + m∠B must equal 90

5x + 3x - 4 = 90

8x = 94

x = 11.75

3 0

3 years ago

the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant

Tamiku [17]

Answer:

The rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters is $24\pi \:\frac{cm^3}{s}$

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

$\frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}$
$\frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}$
The volume of a cone of radius r and height h is given by $V=\frac{1}{3} \pi r^2 h$

We want to find the rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

$\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]$

Substituting the values we know into the above formula:

$\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}$

5 0

3 years ago

Please help me!! Show work please :)

lara31 [8.8K]

Hello!

As you can see, all of these numbers just go down to the tenths, not the hundreds, so we cannot round.

Therefore, the numbers will remain the same.

I hope this helps!

8 0

3 years ago

Read 2 more answers