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mote1985 [20]
3 years ago
8

Simplify and expand (X+3)(x-3)(3x+3)​

Mathematics
2 answers:
ivolga24 [154]3 years ago
7 0

Answer:

3x^3 + 3x^2 - 27x - 27

Step-by-step explanation:

Sunny_sXe [5.5K]3 years ago
3 0
<h3>Answer:    3x^3 + 3x^2 - 27x - 27</h3>

===============================================

Work Shown:

(x+3)(x-3)(3x+3)

(x^2-9)(3x+3) .... difference of squares rule

y(3x+3) .... let y = x^2-9

y*3x + y*3 .... distribute

3x( y ) + 3( y )

3x( x^2 - 9 ) + 3(x^2 - 9) .... plug in y = x^2-9

3x*x^2 + 3x*(-9) + 3*x^2 + 3*(-9) .... distribute

3x^3 - 27x + 3x^2 - 27

3x^3 + 3x^2 - 27x - 27

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Mariulka [41]
The answer is D.

Since the two triangles are congruent, they would have equal angles.

The reason why the other answer choices are wrong...

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C) Line RS is equal to Line XY, not Line ST.
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