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3 years ago

Simplify and expand (X+3)(x-3)(3x+3)

Mathematics

2 answers:

ivolga24 [154]3 years ago

7 0

Answer:

3x^3 + 3x^2 - 27x - 27

Step-by-step explanation:

Sunny_sXe [5.5K]3 years ago

3 0

<h3>Answer: 3x^3 + 3x^2 - 27x - 27</h3>

===============================================

Work Shown:

(x+3)(x-3)(3x+3)

(x^2-9)(3x+3) .... difference of squares rule

y(3x+3) .... let y = x^2-9

y*3x + y*3 .... distribute

3x( y ) + 3( y )

3x( x^2 - 9 ) + 3(x^2 - 9) .... plug in y = x^2-9

3x*x^2 + 3x*(-9) + 3*x^2 + 3*(-9) .... distribute

3x^3 - 27x + 3x^2 - 27

3x^3 + 3x^2 - 27x - 27

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Question 6 (1.25 points)

Lisa [10]

Answer:

Test statistic Z= 1.713

The calculated Z- value = 1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

Step-by-step explanation:

A researcher wants to test if the mean annual salary of all lawyers in a city is

different from $110,000

Mean of the Population μ = $110,000

Sample size 'n' = 53

Mean of the sample x⁻ = $114,000.

standard deviation of the Population = $17,000,

Level of significance = 0.01

Null hypothesis :

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

H₀: x⁻ = μ

Alternative Hypothesis : x⁻ ≠ μ

<u><em>Step(ii)</em></u>:-

Test statistic

$Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{114000-110000}{\frac{17000}{\sqrt{53} } }$

Z = 1.7130

Tabulated value Z = 2.576 at 0.01 level of significance

The calculated Z- value = 1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

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3 years ago

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Answer:

Step-by-step explanation:

So this is multiplication

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