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Licemer1 [7]
3 years ago
12

0.7 of 12.99 how do you solve it?

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
4 0

Answer:

9.093

Step-by-step explanation:

Of means multiply

.7 * 12.99

9.093

vlada-n [284]3 years ago
3 0

Answer:

9,093

Step-by-step explanation:

Yes. You take 70% of 12,99 [multiply].

I am joyous to assist you anytime.

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A small town has two local high schools. High School A currently has 750 students and is projected to grow by 45 students each y
PtichkaEL [24]

Answer: A=750 +75*t

B=900 +25*t

There would be 975 students in each high school in year 3 when they are expected to have the same number of students.

Step-by-step explanation:

A = B

750 +75*t=900 + 25*t

Solving:

75*t -25*t= 900 - 750

50*t= 150

t=3

This indicates that in year 3 both High Schools are projected to have the same number of students. To get that amount, you simply replace this value in the expressions:

A=750 +75*t= 750 +75*3= 975

B=900 + 25*t=900 + 25*3= 975

There would be 975 students in each high school in year 3 when they are expected to have the same number of students.

 

8 0
3 years ago
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If two angles are supplementary, they must __________.
WARRIOR [948]
Supplementary angles add up to 180
6 0
3 years ago
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Which is the equation of a line that has a slope of -2/3and passes through point<br> (-3,-1)?
Nataly [62]
Answer:

y=-2/3x-3



Explanation
4 0
3 years ago
Expres each complex number in polar form. State the arguments in radians rounded to the nearest thousandth.
Arlecino [84]

Answer:

(a) In polar form complex number will be 5.3851\angle 68.1985^{\circ} and in radian argument is 0.378π

(b) 6.0827\angle -9.46^{\circ}

angle will be 0.05255π

Step-by-step explanation:

We have given

(a) 2+5i

We have to represent in polar form

We know that magnitude is given by \sqrt{(real\ part)^2+(imaginary\ part)^2}=\sqrt{2^2+5^2}=\sqrt{29}

Argument is given by tan^{-1}\frac{imaginary\ part}{real\ part}=tan^{-1}\frac{5}{2}=68.198

So in polar form complex number will be 5.3851\angle 68.1985^{\circ}

In radian argument will be 68.1985\times \frac{\pi }{180}=0.378\pi

(b) We have given complex number -6+i

We know that magnitude is given by \sqrt{(real\ part)^2+(imaginary\ part)^2}=\sqrt{(-6)^2+1^2}=\sqrt{37}

Argument is given by tan^{-1}\frac{imaginary\ part}{real\ part}=tan^{-1}\frac{1}{-6}=-9.46

So in polar form complex number will be 6.0827\angle -9.46^{\circ}

In radian argument will be -9.46\times \frac{\pi }{180}=-0.05255\pi

8 0
4 years ago
K=5r-s you are solving for r
Ierofanga [76]
R= s+k/5 this is the answer
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