Answer:
∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG
Step-by-step explanation:
We have that the initial triangles are equal. Let us check which components remain within the final triangles as the same. The only such components are the angles B and C. We now know that we have to apply a triangle equality criterion.
The triangles BGH and CIH are equal since the have 2 common sides and the respective interior angles are equal. Then we have that BI=GC and also that the respective angles B and C are equal. THen also HIJ=HGJ since they fill to 180 degrees with angles that are equal.
Hence by angle-side-angle the triangles BJI and CJG are equal.
∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG
Answer:
10 one-millimeter cubes
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Answer:
- (x -3)^2 +(y -5)^2 = 9
- x^2 +y^2 -6x -10y +25 = 0
Step-by-step explanation:
The standard form equation for a circle of radius r and center (h, k) is ...
(x -h)^2 +(y -k)^2 = r^2
For radius 3 and center (3, 5), this is ...
(x -3)^2 +(y -5)^2 = 9 . . . . standard form equation
Expanding this and subtracting the constant on the right gives ...
x^2 -6x +9 +y^2 -10y +25 -9 = 0
x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation
The type of the line is horizontal.