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natita [175]
3 years ago
12

What is -3(x+9)=15?

Mathematics
2 answers:
m_a_m_a [10]3 years ago
8 0

Answer:

X= -14

Step-by-step explanation:

Vadim26 [7]3 years ago
7 0
Answer is x= -14 because you divide each term by -3 and then simplify
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If 15 people can empty the truck in 60 minutes, how long will it take 25 people to empty the same truck.
nikklg [1K]
60 divide dos by 15 is 4, so it takes 4 minutes for each person to empty it.
25 x 4 = 100, so the answer would be 100 minutes.
8 0
3 years ago
36 POINTS HURRYYYYYY What procedure can be used to solve the equation 540 = StartFraction a Over 11 EndFraction, and what is the
mina [271]

Answer:

Divide StartFraction a Over 11 EndFraction by 11; the solution is 540.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the volume of a pyramid with a square base, where the perimeter of the base is 7.3\text{ ft}7.3 ft and the height of the py
Cloud [144]

Answer:

V=6.66\ ft^3

Step-by-step explanation:

The perimeter of the square base of a pyramid = 7.3 ft

The height of the pyramid, h = 6ft

The perimeter of a square is given by :

P = 4s, s is the side of square

7.3 = 4s

s = 1.825 ft

The volume of a pyramid is given by :

V=\dfrac{lbh}{3}

Here, l = b = 1.825 ft

So,

V=\dfrac{1.825\times 1.825\times 6}{3}\\\\V=6.66\ ft^3

So, the volume of the pyramid is equal to 6.66\ ft^3.

3 0
3 years ago
Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.
kolezko [41]

Answer:

A=4.5u^2

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3

y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9

The integral will be the subtraction of the curve y=3x and y=x^2  (In the graph you can see y=3x is the upper curve):

\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2

6 0
2 years ago
Complete the table of values for this equation:
kow [346]

Answer:

X y

2 30

3 35

4 40

Step-by-step explanation:

Putting the value of x in equation u will get the value of y

4 0
3 years ago
Read 2 more answers
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