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4 years ago

12

If 2^m = 4x and 2^w = 8x, what is m in terms of w?

1 answer:

zimovet [89]4 years ago

7 0

Using the laws of indices, you can solve it.

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If the discriminant is 16 in a quadratic equation what is true about its solutions

olganol [36]

If the discriminant is a positive number, there will be 2 possible solutions. If you replace the entire section of b²-4ac with 16, you will see that the equation becomes; (-b+-√16)/2a --> leading to an answer with the + and another with the -.

If the discriminant is 0, there will be 1 possible solution, (again replace this into the discriminant value) (-b)/2a ---> this formula is used to also find the x coordinates of a vertex, fyi.

If the discriminant is a negative number, there will be no solution (since squareroot of a negative number is not possible)

Hope I helped :)

8 0

3 years ago

harry owes the bank money.To replay his debt,he paid $150 back to the bank each month . After 10 months, his remaining debt was

Maksim231197 [3]

Answer: 8400 $

Explanation:
His original debt: money paid for 10 months + remaining debt
Assume X is his original debt
Then X= 10 • 150 + 6900
X= 1500+6900=8400$

8 0

4 years ago

Call an integer $n$ oddly powerful if there exist positive integers $a$ and $b$, where $b>1$, $b$ is odd, and $a^b = n$. How

azamat

Answer:

There are 16 oddly powerful integers less than 2010

Step-by-step explanation:

∵ b is an odd integer

∵ b > 1

∴ The first value of b is 3

∵ a is an integer

- We can use a = 1, 2, 3, ..........

∵ $a^{b}=n$

∵ n < 2010

- Let a = 1, 2, ............... 12 because 12³ is greatest integer < 2010

∵ 1³ = 1, 2³ = 8, 3³ = 27, 4³ = 64, 5³ = 125, 6³ = 216, 7³ = 343,

8³ = 512, 9³ = 729, 10³ = 1000, 11³ = 1331, 12³ = 1728

∴ There are 12 oddly powerful integers with b = 3

Now the second value of b is 5

$1^{5}=1$ but we took 1 before so we will start with 2

∵ $2^{5}=32$ , $3^{5}=243$ , $4^{5}=1024$

- $4^{5}$ is the greatest integer < 2010

∴ There are 3 oddly powerful integers with b = 5

Now the third value of b is 7

∵ $2^{7}=128$

- $2^{7}$ is the greatest integer < 2010

∴ There is 1 oddly powerful integers with b = 7

Now the fourth value of b is 9

∵ $2^{9}=512$

- $2^{9}$ is the greatest integer < 2010

- But we used 512 before

∴ There is no oddly powerful integers with b = 9

- 9 is the greatest value of b which makes $a^{b}$

∵ 12 + 3 + 1 = 16

∴ There are 16 oddly powerful integers less than 2010

5 0

3 years ago

Mary has to choose between a job and learning French during summer

Andrei [34K]

Answer:

To develop a molecular clock, you need to find which of the following?

a sequence of molecules

the rate at which changes occur in a type of molecule

how much total change has occurred in a type of molecule from two different species

how many molecules a species has

Step-by-step explanation:

To develop a molecular clock, you need to find which of the following?

a sequence of molecules

the rate at which changes occur in a type of molecule

how much total change has occurred in a type of molecule from two different species

how many molecules a species has

4 0

3 years ago

Read 2 more answers

on a piece if paper graph y <-3/4x +2 Then determine which answer choice matches the graph you drew

vichka [17]

Answer: graph d for apex

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers