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3 years ago

Someone help with these its due tomorrow. Ahhhh

Mathematics

1 answer:

Oksana_A [137]3 years ago

4 0

I'll help with 1.)
9m:3m = 6m:x
cross multiply
9x=3*6
9x=18
divide both sides 9
x = 2
the missing side is 2m

The missing angle is 30°

Question 2.)
find the ratios to solve for missing side
24:6 = b:4
cross multiply
24*4 = 6b
96 = 6b
divide both sides by 6
16 = b

The missing angle is 32°

Question 3.)
Find missing side d
make a ratio
5:d = 3:9
cross multiply
5*9 = 3d
45 = 3d
divide both sides by 3
15 = d

the missing angle is 90°

Question 4.)
Find missing side s
write as proportion or ratio
36:6 = s:2
cross multiply
36*2 = 6s
72 = 6s
divide both sides by 6
s = 12

The missing angle t is 71°

Hope this helps :)

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55g as a percentage of 2.2kg

Evgesh-ka [11]

Answer:

2.5%

2.2kg=2200g

<u> $\frac{x}{100} \times 2200 = 55 \\ 22x = 55 \\ x = 2.5\%$ </u>

3 0

3 years ago

HELLPPPPPP PLEASEEE!!!

prisoha [69]

Answer:

Step-by-step explanation:

The first term is 2

Therefor t₁ = 2

Each aditional term is 5 times the previous term

That's the second choice

8 0

3 years ago

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .