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Colt1911 [192]
3 years ago
7

Someone help with these its due tomorrow. Ahhhh

Mathematics
1 answer:
Oksana_A [137]3 years ago
4 0
I'll help with 1.) 
9m:3m = 6m:x
cross multiply
9x=3*6
9x=18
divide both sides 9
x = 2
the missing side is 2m

The missing angle is 30°

Question 2.)
find the ratios to solve for missing side
24:6 = b:4
cross multiply
24*4 = 6b
96 = 6b
divide both sides by 6
16 = b

The missing angle is 32°

Question 3.)
Find missing side d
make a ratio
5:d = 3:9
cross multiply
5*9 = 3d
45 = 3d 
divide both sides by 3
15 = d

the missing angle is 90°

Question 4.)
Find missing side s
write as proportion or ratio
36:6 = s:2
cross multiply
36*2 = 6s
72 = 6s
divide both sides by 6
s = 12

The missing angle t is 71°

Hope this helps :)
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Consider the two data sets below:
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Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

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A certain pet store sells only dogs and cats. In
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They sold 300 dogs and 200 cats
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a straight trail with a uniform inclination of 11 degrees from a lodge at an elevation of 700 feet to a mountain lake at an elev
kozerog [31]

Answer:

r = 38584.155\,ft

Step-by-step explanation:

The length of the trail is obtained by the definition of sine, where height is the opposite leg and length is the hypotenuse:

\tan 11^{\textdegree} = \frac{8200\,ft-700\,ft}{r}

The length of the trail is:

r = 38584.155\,ft

4 0
2 years ago
3.14=7x-2y
eimsori [14]

3.14=7x-2y

move 7x to the other side

sign changes from +7x to -7x

3.14-7x=7x-7x-2y

3.14-7x=-2y

Divide both sides by -2

3.14/-2-7x/-2=-2y/-2

3.14/-2=-1.57

-7x/-2=7x/2

Answer:

y=-1.57+7x/2

5 0
3 years ago
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