Answer:
oh lord...ill try my best
Step-by-step explanation:
Let's start b writing down coordinates of all points:
A(0,0,0)
B(0,5,0)
C(3,5,0)
D(3,0,0)
E(3,0,4)
F(0,0,4)
G(0,5,4)
H(3,5,4)
a.) When we reflect over xz plane x and z coordinates stay same, y coordinate changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.
A(0,0,0)
Reflecting
A(0,0,0)
B(0,5,0)
Reflecting
B(0,-5,0)
C(3,5,0)
Reflecting
C(3,-5,0)
D(3,0,0)
Reflecting
D(3,0,0)
b.)
A(0,0,0)
Moving
A(-2,-3,1)
B(0,-5,0)
Moving
B(-2,-8,1)
C(3,-5,0)
Moving
C(1,-8,1)
D(3,0,0)
Moving
im sorry think this is wrong I TRIED MY BESTTTT!!!!!!!! give me credit this is tiring
The diagram of the lawn and the shed is shown below.
The area of the lawn needed to be mowed equals to the area of the yard minus the area of the shed
The area of the yard =
The area of the shed =
The area of the lawn =
The area of the lawn =
The area of the lawn =
Answer:
No solution
Step-by-step explanation:
6X - 3Y = -9--------------(1)
- 2 X +Y= 5---------------(2)
from equation two,
Y = 5+2X------------------(3)
substitute equation (3) into equation (1)
6X-3(5+2X)= -9
opening bracket
6X-15-6X= -9
6X- 6X = -9+15
0 = 6
<h2>therefore the answer is no solution</h2>
Answer:
26 bags
Step-by-step explanation:
A bag of cat chows = 30 lbs
Amount of cat chows needed in a week = 15 lbs = ½ bag of cat chow
There are at least 52 weeks in a year.
The least number of cat chows bags needed at the shelter in 1 year = 52 weeks × ½ bag of chow
= 52 × ½
= 52/2
= 26 bags of cat chow
At least, 26 bags would be needed in 1 year (52 weeks) at this wild life shelter if 15 lbs is consumed weekly.
If you would like to know whether or not what she wrote is accurate, it is.
Hope that helps!
