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Anestetic [448]
3 years ago
8

Help me I will give extra points

Mathematics
1 answer:
dlinn [17]3 years ago
3 0

Answer: g(x) = -4x + 5

Please mark me brainliest instead of points

You might be interested in
How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used
MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the <em>n</em>-th term of the sequence, <em>a</em> (<em>n</em>), is given recursively by

• <em>a</em> (1) = 1

• <em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 21 … … … for <em>n</em> > 1

We can find the explicit rule for the sequence by iterative substitution:

<em>a</em> (2) = <em>a</em> (1) + 21

<em>a</em> (3) = <em>a</em> (2) + 21 = (<em>a</em> (1) + 21) + 21 = <em>a</em> (1) + 2×21

<em>a</em> (4) = <em>a</em> (3) + 21 = (<em>a</em> (1) + 2×21) + 21 = <em>a</em> (1) + 3×21

and so on, with the general pattern

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 21 (<em>n</em> - 1) = 21<em>n</em> - 20

Now, we're told that the sum of some number <em>N</em> of terms in this sequence is 2332. In other words, the <em>N</em>-th partial sum of the sequence is

<em>a</em> (1) + <em>a</em> (2) + <em>a</em> (3) + … + <em>a</em> (<em>N</em> - 1) + <em>a</em> (<em>N</em>) = 2332

or more compactly,

\displaystyle\sum_{n=1}^N a(n) = 2332

It's important to note that <em>N</em> must be some positive integer.

Replace <em>a</em> (<em>n</em>) by the explicit rule:

\displaystyle\sum_{n=1}^N (21n-20) = 2332

Expand the sum on the left as

\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332

and recall the formulas,

\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n

\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2

So the sum of the first <em>N</em> terms of <em>a</em> (<em>n</em>) is such that

21 × <em>N</em> (<em>N</em> + 1)/2 - 20<em>N</em> = 2332

Solve for <em>N</em> :

21 (<em>N</em> ² + <em>N</em>) - 40<em>N</em> = 4664

21 <em>N</em> ² - 19 <em>N</em> - 4664 = 0

Now for the problem I mentioned at the start: this polynomial has no rational roots, and instead

<em>N</em> = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer <em>N</em> for which the first <em>N</em> terms of the sum add up to 2332.

4 0
2 years ago
So what s the meaning for X and Y
gregori [183]

The first x is the horizontal coodinate (abscisa) and second is the vertical coordinate (ordenate). Both are coordinates. (x,y) has the meaning of a complex number: x is the real part and y is the imaginary part: x+yi. (x,y) has the meaning of a plane's vector from origin of coordinates.

8 0
3 years ago
Simplify square root of 24 times square root of 2x times square root of 3x
sveticcg [70]
\sqrt{24} * \sqrt{2x} * \sqrt{3x} =  \sqrt{2*2*2*3}* \sqrt{2*x} * \sqrt{3*x} =  \sqrt{2*2*2*2*3*3*x*x} = 2*2*3*x = 12x
3 0
3 years ago
How do you find each measure for #7?
Lunna [17]

Step-by-step explanation:

From this figure TUW+WUV=TUV ; (5x+3)+(10x-5)=17x-16 so 15x-2=17x-16 ;14=2x therefore x=7

then substitute x on it.

TUW=5x+3=5(7)+3=35+3=38

WUV=10x-5=10(7)-5=70-5=65

TUV=17x-16=17(7)-16=119-16=103

8 0
3 years ago
What is this? anyone help​
qwelly [4]

Answer:

-a^2 -a -35

Step-by-step explanation:

a(4-a) -5(a+7)

Distribute

4a -a^2 -5a-35

Combine like terms

-a^2+4a -5a-35

-a^2 -a -35

4 0
3 years ago
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