I think it would be 64/100 because 64 percent is most likely out of 100 percent
Answer:
The answer should B, only one makes sense
Answer:
14.2
Step-by-step explanation:
Option first and option second are correct because the common difference of the sequence is the same as the slope of the graph.
<h3>What is a sequence?</h3>
It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
The question is incomplete.
The question is:
What can be concluded about the sequences 19, 15, 11, 7, . . . represented on the graph? Check all that apply.
- The common difference of the sequence is the same as the slope of the graph.
- The slope of the graph is –4.
- The next term in the sequence is represented by point (4, 3).
- f(x) = –4x + 19 represents the sequence.
- An infinite number of points can be determined to follow this sequence.
The graph is attached to the picture please refer to the graph.
We have an arithmetic sequence:
19, 15, 11, 7,...
The first term is:
a = 19
Common difference d = 15-19 = -4
The nth term:
a(n) = 19 + (n-1)(-4)
a(n) = 19 -4n + 4
a(n) = -4n + 23
We can write above expression as:
f(x) = -4x + 23
Slope of the equation = -4
The correct options are:
- The common difference of the sequence is the same as the slope of the graph.
- The slope of the graph is –4.
Thus, an option first and option second are correct because the common difference of the sequence is the same as the slope of the graph.
Learn more about the sequence here:
brainly.com/question/21961097
#SPJ1
Actually, i think something is missing here:
You need either a parenthesis or some dots at the end to determine this. A repeating decimal can have one repreating digit:
0.(7): 0.777777...
two:
0.(45): 0.45454545454545....
or more: so potentially all of them can be repeating, even a!
it could be: 1.(111114)
or: 1.111114111114111114111114111114111114111114111114111114111114111114111114111114...
proably B. is the most typical of repeating decimals (choosed this one if you have to), but in reality, you need more information... did you copy the question exactly?