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Volgvan
3 years ago
5

What is the radius of a circle with an area of 400(pi) cm^2?

Mathematics
1 answer:
ivanzaharov [21]3 years ago
5 0

Answer:  r≈11.28

Step-by-step explanation:

                         

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Find the roots of the parabola given by the following equation <br> 2x^2+5X-9=2x
natta225 [31]

Answer:

x=-3\:or\:x=\frac{3}{2}

Step-by-step explanation:

The given parabola has equation

2x^2+5x-9=2x

We rewrite in standard form to obtain:

2x^2+5x-2x-9=0

2x^2+3x-9=0

Split the middle terms to get:

2x^2+6x-3x-9=0

Factor by grouping:

2x(x+3)-3(x+3)=0

(x+3)(2x-3)=0

x=-3\:or\:x=\frac{3}{2}

7 0
3 years ago
ST=<br> Help me please thank u
dmitriy555 [2]

Step-by-step explanation:

RS + ST = 8

(RS + ST)×RS = (4 + 2)×4

8 × RS = (4 + 2) × 4 = 6 × 4 = 24

RS = 24/8 = 3

RS + ST = 8

3 + ST = 8

ST = 5

8 0
1 year ago
How do you graph -1/5x-1 and 4/5x-6
kakasveta [241]

Answer:

The points for the given to linear equations is (5 , - 2) and (5 , - 1)

The points is plotted on the graph shown .

Step-by-step explanation:

Given as :

The two linear equation are

y = \dfrac{-1}{5}x - 1                  ...........1

y = \dfrac{4}{5}x - 6                  ...........2

Now, Solving both the linear equations

Put the value of y from eq 2 into eq 1

I.e  \dfrac{4}{5}x - 6 = \dfrac{-1}{5}x - 1

Or, \dfrac{4}{5}x + \dfrac{1}{5}x  = 6 - 1

Or,  \dfrac{4 + 1}{5}x = 5

or, \dfrac{5}{5}x = 5

∴ x = 5

Now, Put the value of x in eq 1

So, y = \dfrac{-1}{5}x - 1      

Or, y = \dfrac{-1}{5}× 5 - 1              

or,  y = \dfrac{-5}{5} - 1

Or, y = - 1 - 1

I.e y = -2

So, For x = 5 , y = - 2

Point is (x_1 , y_1) = (5 , - 2)

Again , put the value of x in eq 2

So, y = \dfrac{4}{5}x - 6

Or, y = \dfrac{4}{5}× 5 - 6

Or, y = \frac{4\times 5}{5} - 6

Or, y = 4 - 6

I.e y = - 2

So, For x = 5 , y = - 2

Point is (x_2 , y_2) = (5 , - 2)

Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)

The points is plotted on the graph shown . Answer

5 0
3 years ago
Laura's uncle donated 120 cans of juice and 90 packs of cheese crackers for the school picnic. Each student is to receive the sa
liubo4ka [24]

Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30  What I did next was  divide thirty by the number of  cracker and also by the number of can of juice.

120÷30= 4

90÷30=  3

So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.


I hope you enjoyed my explanation. :)

3 0
3 years ago
Read 2 more answers
Press on the picture
scoray [572]
B is the correct answer
7 0
2 years ago
Read 2 more answers
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