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Mashcka [7]
3 years ago
9

Jane is fencing in her backyard. The yard is a rectangular area where one side

Mathematics
1 answer:
Sedaia [141]3 years ago
4 0

Answer:  2x + 40 = 150

Step-by-step explanation:

Jane has 150 feet of fencing.  40 feet will go for the portion opposite the house,  The remaining fencing will go for the two sides of equal length x.  That makes 2x for both.  So:

<u>2x + 40 = 150</u>

[x = 55 feet]

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ASAP I NEED AN ANSWER
beks73 [17]

Answer:

His brother gets 8 apples

His friends gets 4 apples

He gets 12 apples

Step-by-step explanation:

brother: friend himself::total

2                1          3        2+1+3 = 6

He has a total of 24 apples

24/6 = 4

Multiply each term by 4

brother: friend himself::total

2*4           1*4        3*4        6*4

8                4          12           24

His brother gets 8 apples

His friends gets 4 apples

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5 0
2 years ago
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The sum of three different numbers is 18. If every number is a prime number, what are the tree numbers?
Airida [17]
Prime numbers are numbers that don't have more than two factors, therefore 2, 5, and 11are prime numbers. 2+5+11=18. the answer is 2, 5, and 11.
8 0
4 years ago
Can someone please help with this problem ASAP!!!
Ira Lisetskai [31]

Answer:

Step-by-step explanation:

(1,5 ) indicates that for every 1 book they make 5 dollars so the point means that for every book they sell they make 5 dollars.

7 0
3 years ago
4. Find the center and the radius of the circle which circumscribes the triangle with vertices ai, a, a3. Express the result in
Mama L [17]
<h2>Answer:</h2>

<u>\left[\begin{array}{ccc}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{array}\right]=\left[\begin{array}{ccc}-a_{1}^{2}-b_{1}^{2}\\-a_{2}^{2}-b_{2}^{2}\\-a_{3}^{2}-b_{3}^{2}\end{array}\right]</u>

<h2>Step-by-step explanation:</h2>

In the question,

We have to find out the circumcentre of the circle passing through the triangle with the vertices (a₁, b₁), (a₂, b₂) and (a₃, c₃).

So,

The circle is passing through these points the equation of the circle is given by,

x^{2}+y^{2}+ax+by+c=0

On putting the points in the circle we get,

x^{2}+y^{2}+ax+by+c=0\\(a_{1})^{2}+(b_{1})^{2}+a(a_{1})+b(b_{1})+c=0\\and,\\(a_{2})^{2}+(b_{2})^{2}+a(a_{2})+b(b_{2})+c=0\\and,\\(a_{3})^{3}+(b_{3})^{3}+a(a_{3})+b(b_{3})+c=0\\

So,

(a_{1})^{2}+(b_{1})^{2}+a(a_{1})+b(b_{1})+c=0\\a(a_{1})+b(b_{1})+c=-(a_{1})^{2}-(b_{1})^{2}\,.........(1)\\and,\\a(a_{2})+b(b_{2})+c=-(a_{2})^{2}-(b_{2})^{2}\,.........(2)\\and,\\a(a_{3})+b(b_{3})+c=-(a_{3})^{3}-(b_{3})^{3}\,.........(3)\\

On solving these equation using, <u>Matrix method we can get the required equation of the circle,</u>

<u>\left[\begin{array}{ccc}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{array}\right]=\left[\begin{array}{ccc}-a_{1}^{2}-b_{1}^{2}\\-a_{2}^{2}-b_{2}^{2}\\-a_{3}^{2}-b_{3}^{2}\end{array}\right]</u>

<em><u>This is the required answer.</u></em>

3 0
3 years ago
Please help! Brainliest to best answer!!
guajiro [1.7K]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
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