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Scorpion4ik [409]
4 years ago
14

Why do we classify lionfish populations near the eastern united states as an invasive species? what suggests that these new popu

lations are not an expansion of the lionfish's natural range? view available hint(s) why do we classify lionfish populations near the eastern united states as an invasive species? what suggests that these new populations are not an expansion of the lionfish's natural range? lionfish are native to the tropical pacific. there are no natural water routes of warm water between the pacific and atlantic oceans. lionfish are native to cold waters near the tip of south america. they could not survive in the warmer waters between their native areas and the colder waters of the east coast of the united states. so, it is very unlikely that these south american populations naturally spread north. lionfish are not good swimmers and have no other mechanisms to spread their populations over great distances. lionfish eat only a few specific types of algae that live in isolated regions of the pacific. if lionfish spread much beyond their native pacific home, they would have nothing to eat?
Biology
1 answer:
strojnjashka [21]4 years ago
6 0

The answer is  Lionfish are native to the tropical Pacific. There are no natural water routes of warm water between the Pacific and Atlantic oceans.

Invasive species is a species that colonizes an environment in which it is not a native species and tends to upset the natural balance of that environment. Lionfish are naturally found in the indo-pacific, which is their native environment. However, their presence in the eastern United States has have threatened the ecosystem of the region. The fish has decimated fisheries and reef ecosystem since they also don’t have natural predators in the region. Therefore, their population explodes unchecked.


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a plant that is homozygous for red fruit is crossed with a plant that has yellow fruit. what wouls be the genotypes and phenotyp
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Answer:

Let's consider that red fruit is dominant over the yellow fruit.

<em>The phenotype of the red fruit of P1 will be red fruit and the genotype will be  RR.</em>

<em>The phenotype of the yellow fruit of P1 will be yellow fruit and the genotype will be rr.</em>

To check the outcomes of the F1 generation, lets cross the P1 generation:

       r      r

R   Rr     Rr

R   Rr     Rr

<em>The results show that all the offsprings from the F1 generation will show the dominant phenotype which is red fruit and they will have Rr genotype. </em>

<em></em>

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Why might genetically engineering a crop to be herbicide resistant result in producing weeds that are herbicide resistant?
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3 years ago
In rabbits, short hair is due to a dominant allele, S, and long hair to its recessive allele, s. Black hair is due to a dominant
Natali5045456 [20]

Answer:

SsBB x SsBB

or

SsBB x SsBb

Explanation:

SS- short hair

ss - long hair

BB- black hair

bb- white hair

Total the number of offspring produced = 2518+817=3335

Where 2518= short haired, black offspring SSBB or SsBb

817= Longed Hair, black offspring ssBB or ssBb

To get the offspring proportion for short hair black offspring

2518/3335×100 = 75.5%

long-haired, blackoffspring =817/3335×100 = 25%

This gives ratio of 3:1 as against the proposed dihybrid phenotypic ratio of Mendel experiment 9:3:3:1

Now, if you remember a dihybrid cross results in 9:3:3:1 phentoype ratio. That is when both parents are heterozygous for both alleles. So we can rule that out since it doesn't match our 3:1 ratio.

Since all the offspring are black , it means one parent is homozygous dominant for black and the other parent is either homozygous or heterozygous for the black allele.

Since the ratio is 3:1, for the hair length

That leaves us with the short hair. Since the ratio is 3:1, both parents are heterozygous for hair length.

Therefore, the possible parental genotype is

SsBB x SsBB

or

SsBB x SsBb

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