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Gekata [30.6K]
3 years ago
10

Is #1 correct and I need help on #2 THANKS :)

Mathematics
1 answer:
horsena [70]3 years ago
6 0
Answer 1 = I believe you are correct cause when doing area , remembering you times the different area of the sides


Answer 2 = I believe the answer is C (2,0009) cause remember adding when doing volume but there are few steps ..
. i have done the work for this and hoping my work helped the answer i got help you! comment below if you need anything , thanks , have a nice day!!
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tester [92]

Answer:

D; is the right answer hope it helps ;)

Step-by-step explanation:

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Simplify (3x2y)(5x3y−1)
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Answer:

6xy(15xy−1)

Step-by-step explanation:

3 0
2 years ago
FACTOR EACH EXPRESSION, IF IT CANT BE FACTORED WRITE CANNOT BE FACTORED. 1. 4x+12
dimaraw [331]
1.) 4(x+3)
Find the GCF, Greatest Common Factor, of 4x and 12. 
4x=2*2*x
12=3*2*2
The greatest common factor is 4. Put this outside of the parentheses.             (You would multiply the 2*2)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
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To check, distribute to see if it works.

4x+12

2.) 2(4r+7)
Find the GCF of 8r and 14
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Then, put the rest of the factors as a sum. (Only the factors on the same line.)
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To check, distribute to see if it works.

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Do you get it now?

3.) 5(x+7)
4.) 7(2x+1)
5.) Cannot be factored.

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Find the GCF of 32x and -15

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-15: -1*5*3

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6.)  8(4x+3)
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8.) 24(1x+2)
9.) 9(-2x+8)
10.) Cannot be factored
11.) 8(1x+3)
12.) 50(1x+5)



4 0
3 years ago
Read 2 more answers
The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati
Stolb23 [73]

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

3 0
3 years ago
I need help pleaseew
Andrews [41]

Answer:

acer hope this helps (:

3 0
3 years ago
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