The answer is no because after each 3 there is one more zero added
to be repeating the number of zeros would have to stay the same
No, you would only need to multiply 16 by 5 once
The equation is <span>f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
remark:
the sum of coefficients is = 2-9+12-12+10-3=-7+7=0, so a=1 is a zero of f
f can be written as </span>f(x) = (x-1)Q(x), and f(x) / (x-1)= Q(x)
after euclid's division
Q(x) = 2x4 - 7x3 + 5x2 - 7x +3
so for finding the other roots, making Q(x) for product of factors is a must
The answer is A =80 because when u add 46+32 =78 and 78 round to the nearest ten is 80
0.0340909091 is the answer
