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Wewaii [24]
3 years ago
5

How to solve −3−6c=9c+5−15c

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
7 0
Can salvage 15c+ -15c is 0 + 8 is still 0
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after five years of earning interest at an annual rate of 4% and investment has earned $1,200 in interest determine the amount o
loris [4]

Answer:

$6000

Step-by-step explanation:

$1200/5years =$240/1yr

$240=4%

:. 1%=$60

Initial investment =$60*100%=$6000

6 0
4 years ago
What is the pre-image of vertex A' if the image shown on
lisov135 [29]

Answer: B. (-6, 8).

Step-by-step explanation:

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3 years ago
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You put $500 into an account and left it alone for three years earning simple interest. At the end of three years, you withdrew
OLga [1]

Answer:

that would mean 15$ a year

1.25$ a month

Step-by-step explanation:

hope it helped

5 0
3 years ago
2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de
Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


3 0
4 years ago
Read 2 more answers
Armando used algebra tiles to represent the product 3 x (2 x minus 1). An algebra tile configuration. 3 tiles are in the Factor
EleoNora [17]

Answer:

Some of the products do not show the correct powers of x.

Step-by-step explanation:

From the picture,

3x(2x - 1) = 6x² - 3x

The correct display on the tile should look like this :

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+x __ +x² ______+x² ______+x²

|

+x__ +x² ______ +x² ______+x²

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- ___ -x _______ -x _______-x

+6x² - 3x

5 0
3 years ago
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