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Elan Coil [88]
3 years ago
12

Solve for r. k=3r-7s

Mathematics
1 answer:
const2013 [10]3 years ago
5 0
R=7s/3+k/3

Hope this helps!
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Tyina is buying 12 shirts for the drama club. She will
Stolb23 [73]
Answer: if you times 12x2.75 I got 33 some she can spend $33.00 and not go over.

3 0
4 years ago
Write an equation for the line in slope- intercept form. 2. Х -4 -2 o 2 4. -2 4​
Alla [95]

Answer:

y= -2x-3

Step-by-step explanation:

this is because the y intercept is at negative 3 and the rise over run is down 1 over 2

3 0
3 years ago
A recipe says to use 3cups of flour to make 48 cookies. What is a constant of proportionality that related the number of cookies
MA_775_DIABLO [31]

Answer:

y=16 x=1

Step-by-step explanation:

For this one, we need to find the unit rate, which means how many cookies we can make using 1 cup of flour. To do that, we need to divide both the flour and the cookies by 3 to get 3/3=1 and 48/3=16. So the total amount of cookies made with one cup of flour is 16. So the constant proportionality is 16,1.

6 0
3 years ago
In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt
kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable

            aluminum from the delivery truck to a storage area. A smaller belt

            moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are​ used, find how long it takes to move the cans

              to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = \frac{1}{4} shifting/min

Rate of Smaller Belt = \frac{1}{6} shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = \frac{1}{x} shifting/min

Now,

\frac{1}{4}  + \frac{1}{6}  = \frac{1}{x}

⇒\frac{6 + 4}{24} = \frac{1}{x}

⇒\frac{10}{24} = \frac{1}{x}

⇒10x = 24

⇒x = \frac{24}{10} = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0
3 years ago
If g(x)=x^2-5x+8, find g(8)
ycow [4]

Answer:

Option A) 32

Step-by-step explanation:

Given the quadratic function, g(x) = x²- 5x + 8:

In order to evaluate and determine the output value given g(8), substitute the input value into the function:

g(x) = x²- 5x + 8

g(8) = (8)²- 5(8) + 8

g(8) = 64 - 40 + 8

g(8) = 32

Therefore, the correct answer is Option A) 32.

5 0
3 years ago
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