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denpristay [2]
3 years ago
13

Tell whether each equation has one, zero, or infinitely many solutions.5(x - 3) +6= 5x - 9​

Mathematics
2 answers:
stellarik [79]3 years ago
8 0

Answer:

Infinitely  many.

Step-by-step explanation:

5(x - 3) +6= 5x - 9

5x - 15 + 6 = 5x - 9

5x - 9 = 5x - 9.

We can enter any real value of x and both sides will be equal so there are infinitely many solutions.

yuradex [85]3 years ago
6 0

Answer:

Infinitely many solutions

Step-by-step explanation:

the 5x's cancel and -15 + 6 = -9 so -9 equals -9. No matter what value you input for x, the answer is equal.

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Which of the following statements about an ellipse is NOT true?
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Answer: (b) The focus of an ellipse is always located precisely at the center of the ellipse.

Step-by-step explanation:

An ellipse is defined as <em>"a closed curve with two axes of symmetry (major axis and minor axis) that results in cutting the surface of a cone by an oblique plane to the axis of symmetry with an angle greater than that of the generatrix with respect to the axis of revolution"</em>. That is why the ellipse is considered a conic figure.

To understand it better: an ellipse has two points on its major axis that are equidistant from the center , which are called foci,  being this distance constant. In addition, the eccentricity allows to know how far the foci are from the center of the ellipse.

Therefore, the statement that indicates an ellipse has only one focus located  precisely at the center is incorrect.

7 0
3 years ago
Someone please help me thank you
Igoryamba

Answer:

x = - 1

Step-by-step explanation:

Given

4x = x^2 - 5               Transfer 4x to the right side.

Solution

x^2 - 4x - 5 = 0          Factor

(x - 5)(x + 1)

You want the negative solution. That means that the middle sign must be plus.

x + 1 = 0                   Subtract 10 from both sides

x = - 1                       Ten on the left disappears by the subtraction process.

Is that correct?

4x = x^2 - 5

x = - 10

4*(-1) = (-1)^2 - 5

-4  = ? 1 - 5

-4 = - 4

and it does work.  

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