A fountain shoots water into the air. The graph shows a water droplet's height y in feet x seconds after it is shot from the fou
2 answers:
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I think I know how to do it
Your equation is:
P₁V₁ = P₂V₂
You Know:
Initial:
P₁ = 84 Pa
V₁ = 336 L
New:
P₂ = ?
V₂ = 216L
Plug this into the equation:
P₁V₁ = P₂V₂
(84 Pa)(336 L) = P₂(216 L) Divide 216 on both sides
130.6666666 = P₂
(if your doing significant figures, you have 2 sig figs)
130 Pa = P₂
Answer:
<em>The x-coordinate is changing at 10 cm/s</em>
Step-by-step explanation:
<u>Rate of Change</u>
Suppose two variables x and y are related by a given function y=f(x). If they both change with respect to a third variable (time, for instance), the rate of change of them is computed as the derivative using the chain rule:
We have
Or, equivalently
We need to know the rate of change of x respect to t. We'll use implicit differentiation:
Solving for dx/dt
Plugging in the values x=1, y=3, dy/dt=5
The x-coordinate is changing at 10 cm/s