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3 years ago

In the function f(t) = sin(t), what is the effect of multiplying t by a coefficient of 2?

Mathematics

1 answer:

liubo4ka [24]3 years ago

5 0

Answer:

"changes the period to pi"

Step-by-step explanation:

f(t) = Sin(t),

Here, t is the period, by definition.

Multiply t by a number that is GREATER THAN 1, makes the period shorter and compressed.

Multiplying t by a number that is between 0 and 1 makes the period expanded.

For the first, if we multiply the period by a, the period becomes $\frac{2\pi}{a}$

Since the problem tells us to multiply by 2, we know the period becomes compressed and becomes :

$\frac{2\pi}{2}=\pi$

Third answer choice is right.

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The function f(t) = 4t^2 − 8t + 6 shows the height from the ground f(t), in meters, of a roller coaster car at different times t

andreev551 [17]

Answer:

C - f(t) = 4(t − 1)^2 + 2; the minimum height of the roller coaster is 2 meters from the ground.

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(To be continued)

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3 years ago

What is 75 equals 6 multiplied by w

guajiro [1.7K]

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3 years ago

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Please help! I'll mark you brainliest :D

Grace [21]

Answer:

range: -3<x<7

Step-by-step explanation:

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3 years ago

A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of

jenyasd209 [6]

Answer:

Ix = Iy = $\frac{ρπR^{4} }{16}$

Radius of gyration x = y = $\frac{R}{4}$

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is $\frac{MR^{2} }{2}$ . Moment of inertia of quarter disk about its perpendicular is $\frac{MR^{2} }{8}$ .

Now using perpendicular axis theorem, Ix = Iy = $\frac{MR^{2} }{16}$ = $\frac{ρπR^{4} }{16}$ .

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

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