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loris [4]
3 years ago
14

Graph the solution set for the inequality x-2/-3 ≤ -5/6

Mathematics
2 answers:
ZanzabumX [31]3 years ago
4 0
Answer: x ≤ 1/6
Explanation: Solve for x
by simplifying both sides of the inequality, then isolating the variable.
zhuklara [117]3 years ago
3 0

Answer:

x \leq - 3/2 (The graph is the image I attached)

Explanation:

1) Determine the sign of the fraction next to the variable, in this case, it's positive, which turns the equation into : x + 2/3 \leq - 5/6

2) Move the constant to the right so that x is only on one side, this then turns the equation into: x \leq - 5/6 - 2/3

3) Subtract the fractions, and the answer is x \leq  -3/2

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0.000626 L is the same as 6.26 cm3. <br> a. True<br> b. False
Elan Coil [88]
One litre is equivalent to 1000 centimetres cubed.

0.000626 x 1000 = 0.626

Therefore, it is b) or false.
6 0
3 years ago
A university is trying to determine if certain remedial classes need to be offered to their incoming class. To do so, they give
lora16 [44]

Answer:

The experiment is identifying whether a student gets less than a 75% on the entrance exam.

The trial is one exam being taken.

An outcome is a student scoring 80%.

Step-by-step explanation:

An experiment occurs when an intervention is made by a researcher and its effect are studied, thus the experiment here is identifying whether a student gets less than a 75% on the entrance exam.

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8 0
3 years ago
If the radius of a circle is 4 1/4 feet, what is the diameter
iragen [17]
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4 0
2 years ago
a cardboard box holds 31.25 cubic inches of creamy butter. The butter is molded into a square prism that is 5 inches long. How m
lesya [120]

Answer:

62.5 \:in^2

Step-by-step explanation:

Volume of the butter in the cardboard = 31.25 cubic inches

Length of the Molded Square Prism =5 Inches

Let the length of the square cross sectional area = x

Volume of the Prism=x^2l

Since l=5 Inches

5x^2=31.25\\x^2=6.25\\x=2.5\: Inches

Next, we determine the surface area of the New Cardboard box to be made.

Length of the Cardboard Box=5 Inches

Length of the square cross sectional area = 2.5 Inches

Total Surface Area=2(x^2+xl+xl)=2(x^2+2xl)

=2(2.5^2+2(2.5)(5))\\=2(6.25+25)\\=2*31.25\\=62.5 \:in^2

Therefore, 62.5 \:in^2 of cardboard is needed,

4 0
3 years ago
Solve. -4 is greater than -4/3s <br><br> −4 &gt; − 4/3 s
alekssr [168]

Answer:

s>3

Step-by-step explanation:

Step 1: Flip the equation.

-4/3s <-4

Step 2: Multiply both sides by 3/(-4).

(3/-4) x (-4/3s) < (3/-4) x (-4)

s > 3

7 0
3 years ago
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