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nevsk [136]
3 years ago
14

How many times larger is 3.19 x 10^8 than 8.23 x 10^5? SHOW YOUR WORK!!!

Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0

In order to find the number times something is larger than something, you have to use division where you divide the larger number by the smaller number.

So:

\frac{3.19*10^8}{8.23*10^5} =387.6063183

I'm not sure how much you want to round to,  but the answer is 387.6063183 times.

You can make sure by multiplying the smaller number by 387.6063183 and you should get the larger number:

8.25*10^5*387.6063183=3.19*10^8

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The sum of five different positive integers is 320. The sum of the greatest three integers in this set is 283. The sum of the gr
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Let a,b,c,d,x represent the five integers in Ascending order.

Given;

The sum of five different positive integers is 320

a+b+c+d+x = 320 .......1

The sum of the greatest three integers in this set is 283

c+d+x = 283 .....2

The sum of the greatest and least integers is 119

a+x = 119 ......3

For the largest possible value;

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3 years ago
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