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3 years ago

What is the equation of the line that passes through the point (-9. 6) and is

Mathematics

1 answer:

hram777 [196]3 years ago

6 0

Answer:

The perpendicular equation is y = -3x -21

Step-by-step explanation:

Perpendicular lines have the exact opposite slope as the other equation and they never have the same y-intercept.

To find the perpendicular slope just look at the slope in the original equation and get the exact opposite.

First let's simplify the equation.

-5 + x = 3y (divide by 3 on both sides to get y by itself)

-5/3 + 1/3x = y or y = 1/3x + 5/3

The exact opposite of this slope would be -3.

Now plug in the point you were given so that we can find the y-intercept.

6 = -3(-9) + b (b = y-intercept)

6 = 27 + b (subtract 27 on both sides)

-21 = b

So the perpendicular equation looks like this.

y = -3x -21

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65% of what number is 39 then write an equation

Volgvan

Answer:

Step-by-step explanation:

65% = .65, so

60 × .65 = 39

or the equation could be

60/.65 = x

Hope this helps, if not please let me know and i will do my best to correct my mistake.

6 0

3 years ago

The table represents a linear function. Find the values of A and B.

bazaltina [42]

Answer:

The answers are that a = -5 and b = 1

Step-by-step explanation:

In order to find A and B, we first need to find the equation of the line. We can do this by using two ordered pairs and the slope formula. For the purpose of this activity, I'l use (0, 5) and (-3, 11)

m(slope) = (y2 - y1)/(x2 - x1)

m = (11 - 5)/(-3 - 0)

m = 6/-3

m = -2

Now that we have this we can model this using point-slope form.

y - y1 = m(x - x1)

y - 5 = -2(x - 0)

y - 5 = -2x

y = -2x + 5

Now that we have the modeled equation we can use the ordered pair (a, 15) to solve for a.

y = -2x + 5

15 = -2(a) + 5

10 = -2a

-5 = a

And we can also solve for b using the ordered pair (2, b)

y = -2x + 5

b = -2(2) + 5

b = -4 + 5

b = 1

4 0

3 years ago

Use the matrix tool to solve the system of equations 5x+2y=1 and -x-y=-2

Aleks [24]

Answer:

Step-by-step explanation:

$1.5x+2y=1\\2.-x-y=-2\\2.2(-x-y=-2)\\5x+2y=1\\-2x-2y=-4 +\\3x=3\\x=1\\Substitute into number one\\5+2y=1\\y=-2$

6 0

4 years ago

What is the surface area of the triangular prism?

Elanso [62]

Answer:

135 square feet

Step-by-step explanation:

area of base and top=2(1/2×6×2.5)=15 square feet.

area of three faces=(2.5+6+6.5)×8=15×8=120 ft

total surface area=15+120=135 square feet.

4 0

3 years ago

Read 2 more answers

Find the p-value: An independent random sample is selected from an approximately normal population with an unknown standard devi

vladimir1956 [14]

Answer:

(a) p-value = 0.043. Null hypothesis is rejected.

(b) p-value = 0.001. Null hypothesis is rejected.

(d) p-value = 0.022. Null hypothesis is rejected.

Step-by-step explanation:

To test for the significance of the population mean from a Normal population with unknown population standard deviation a t-test for single mean is used.

The significance level for the test is α = 0.05.

The decision rule is:

If the p - value is less than the significance level then the null hypothesis will be rejected. And if the p-value is more than the value of α then the null hypothesis will not be rejected.

(a)

The alternate hypothesis is:

Hₐ: μ > μ₀

The sample size is, n = 11.

The test statistic value is, t = 1.91 ≈ 1.90.

The degrees of freedom is, (n - 1) = 11 - 1 = 10.

Use a t-table t compute the p-value.

For the test statistic value of 1.90 and degrees of freedom 10 the p-value is:

The p-value is:

P (t₁₀ > 1.91) = 0.043.

The p-value = 0.043 < α = 0.05.

The null hypothesis is rejected at 5% level of significance.

(b)

The alternate hypothesis is:

Hₐ: μ < μ₀

The sample size is, n = 17.

The test statistic value is, t = -3.45 ≈ 3.50.

The degrees of freedom is, (n - 1) = 17 - 1 = 16.

Use a t-table t compute the p-value.

For the test statistic value of -3.50 and degrees of freedom 16 the p-value is:

The p-value is:

P (t₁₆ < -3.50) = P (t₁₆ > 3.50) = 0.001.

The p-value = 0.001 < α = 0.05.

The null hypothesis is rejected at 5% level of significance.

(c)

The alternate hypothesis is:

Hₐ: μ ≠ μ₀

The sample size is, n = 7.

The test statistic value is, t = 0.83 ≈ 0.82.

The degrees of freedom is, (n - 1) = 7 - 1 = 6.

Use a t-table t compute the p-value.

For the test statistic value of 0.82 and degrees of freedom 6 the p-value is:

The p-value is:

P (t₆ < -0.82) + P (t₆ > 0.82) = 2 P (t₆ > 0.82) = 0.444.

The p-value = 0.444 > α = 0.05.

The null hypothesis is not rejected at 5% level of significance.

(d)

The alternate hypothesis is:

Hₐ: μ > μ₀

The sample size is, n = 28.

The test statistic value is, t = 2.13 ≈ 2.12.

The degrees of freedom is, (n - 1) = 28 - 1 = 27.

Use a t-table t compute the p-value.

For the test statistic value of 0.82 and degrees of freedom 6 the p-value is:

The p-value is:

P (t₂₇ > 2.12) = 0.022.

The p-value = 0.444 > α = 0.05.

The null hypothesis is rejected at 5% level of significance.

5 0

4 years ago