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AleksAgata [21]
3 years ago
9

Graph y=-(x-1) Can someone help me?

Mathematics
1 answer:
shepuryov [24]3 years ago
7 0
Its a solid line going down with a x-intercept of (1, 0) and y-intercept of (1, 0)

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RoseWind [281]
Peter answered 9 of the questions correctly. 15 divided by 100 to get .15 and then multiply by 60 to get 9. Got 9 correct, 7 incorrect.
5 0
4 years ago
The slope of the line below is -4 use the coordinates of the label point to find a point slope equation of the line (4,-9)
zalisa [80]

Point slope form: y1-y2=m(x1-x2)

Given the slope -4 and the set of coordinates (4,-9),

y+9=-4(x-4)

I plugged in the slope and coordinates. Since -9 came after a subtraction sign, I corrected the subtraction to addition, leaving the above point slope form equation.

I hope this helps :)


7 0
4 years ago
Read 2 more answers
Which describes the correlation shown in the scatterplot?​
Alexus [3.1K]

Answer:

Option.B

There is a negative correlation in the data set

5 0
3 years ago
Solve the equation. (-7x + 2)^1/3 = (4 + 3x)^1/3
Brrunno [24]
(-7x + 2)^1/3 = (4 + 3x)^1/3
take the cube of both side to eliminate the 1/3 power
so you get
-7x+2=4+3x
combine like terms
-10x=2
solve for x
x=-1/5
3 0
3 years ago
A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh
aleksklad [387]

The spider's movement is an illustration of a parabola.

  • The equation of a parabola is: \mathbf{y = -\frac{1}{160}(x - 40) + 10}
  • The focus of a parabola is: (40,-30)
  • The axis of symmetry is: \mathbf{x = 40}
  • The directrix is:\mathbf{y = 50}

<u>(a) The equation</u>

The spider passes through the origin.

So, we have:

\mathbf{(x,y) = (0,0)}

The spider jumps to a maximum height of 10mm, midway 80mm.

So, the vertex is:

\mathbf{(h,k) =  (40,10)}

The equation of a parabola is:

\mathbf{y = a(x - h)^2 + k}

So, we have:

\mathbf{0 = a(0 - 40)^2 + 10}

Subtract 10 from both sides

\mathbf{a(0 - 40)^2 =- 10}

\mathbf{1600a =- 10}

Solve for a

\mathbf{a =- \frac{1}{160}}

Substitute \mathbf{a =- \frac{1}{160}} and \mathbf{(h,k) =  (40,10)} in \mathbf{(h,k) =  (40,10)}

\mathbf{y = -\frac{1}{160}(x - 40) + 10}

<u>(b) The focus, directrix and the axis of symmetry</u>

The focus of a parabola is:

\mathbf{Focus= (h, k + p)}

Where:

\mathbf{p = \frac{1}{4a}}

So, we have:

\mathbf{p = \frac{1}{4 \times -1/160}}

\mathbf{p = -\frac{160}{4}}

\mathbf{p = -40}

So, we have:

\mathbf{Focus = (40,10-40)}

\mathbf{Focus = (40,-30)}

The axis of symmetry is:

\mathbf{x = h}

So, we have:

\mathbf{x = 40}

The directrix is:

\mathbf{y = k - p}

\mathbf{y = 10 + 40}

\mathbf{y = 50}

Read more about parabolas at:

brainly.com/question/25237745

4 0
3 years ago
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