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Minchanka [31]
3 years ago
5

Sam built a circular fenced-in section for some of his animals. The section has a circumference of 55 meters. What is the

Mathematics
1 answer:
Vinvika [58]3 years ago
3 0

Answer:

my fault pimp i aint know the answer

Step-by-step explanation:

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One year after you buy a tree, it is 15 feet tall. Each year after you buy the tree, it grows 2.5 feet. Write a function that re
stiv31 [10]

Answer:

hey! this is your answer:

Step-by-step explanation:

function =

f(n)= 2.5n + 15

It takes 4 years for it to grow to 25 ft.

becuase,

25= 2.5(4) + 15

the equation equals itself out when 4 is put in.

6 0
3 years ago
If f(x)=3x^2-2x+4 and g(x)=5x^2+6x-8,find (f-g) (x)
lawyer [7]

Answer:

-2x^2-8x+12

Step-by-step explanation:

f(x)=3x^2-2x+4

g(x)=5x^2+6x-8

(f-g) (x)= 3x^2-2x+4 - (5x^2+6x-8)

Distribute the minus sign

(f-g) (x)= 3x^2-2x+4 - 5x^2-6x+8

Combine like terms

          =-2x^2-8x+12

4 0
3 years ago
Read 2 more answers
Naming with the vertex only won't work when there are multiple angles with the same vertex. True or False?
Lyrx [107]
True
Extra characters
5 0
3 years ago
What is the solution to the equation? x = 1 x = 6 x = 12 x = 24
stiks02 [169]

Answer:

<h2>X=6</h2>

Option B is the correct option

solution,

\sqrt{5x - 7}  =  \sqrt{3x + 5}

Cancel the square roots on both sides

5x - 7 = 3x + 5

Add 7 to both sides

5x - 7 + 7 = 3x + 5 + 7

Simplify

5x = 3x + 12

Subtract 3x from both sides

5x - 3x = 3x + 12 - 3x

Simplify

2x = 12

Divide both sides by 2

\frac{2x}{2}  =  \frac{12}{2}

Simplify

x = 6

Hope this helps...

Good luck on your assignment..

4 0
3 years ago
I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
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