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3 years ago

The weekly salaries (in dollars) for

Mathematics

1 answer:

kompoz [17]3 years ago

8 0

Answer:

a) Median stays the same

b) Mean is decreased by $9

Step-by-step explanation:

The median is the number or the average of the two numbers that is in the middle of a sorted distribution of numbers,

Here the median number will be the 5th number counting from left or right from the sorted list of numbers. Therefor is is 891.

When 1027 is changed to 946 it will fall between 938 and 1002. So updated sorted list of numbers will now look like,

679, 715, 799, 844, 891, 917, 938, 946, 1002

Here also median will be the 5th number which will be equal to 891.

Therefore, , median will not change.

Mean is the value we get by taking the total value of the salaries and divide it by the number of employees.

In the initial case,

Mean = $\frac{679+715+799+844+891+917+938+1002+1027}{9} =868$

When the salary is changed from $1027 to $946,

Mean= $\frac{679+715+799+844+891+917+938+1002+946}{9} =859$

Therefor we can see that Mean has decreased by $9.

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What are the points of discontinutity y=(x-3)/x^2-12x+27

madreJ [45]

Answer:

$(3, -\frac{1}{6})$

Step-by-step explanation:

We can rewrite the equation as

$y = \frac{x - 3}{(x - 3)(x - 9)}$

Notice that we have $x - 3$ in both the numerator and the denominator, so it looks like we can divide it out. However, what if $x - 3$ is $0$ ? Then we would have $y = \frac{0}{0 \times (x - 9)} = \frac{0}{0}$ , which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for $x = 3$ , but this one is not).

A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at $x = 3$ . In the simplified version of the function, if we plug in $x = 3$ , we get

$y = \frac{1}{((3) - 9)} = -\frac{1}{6}$

So the point $(3, -\frac{1}{6})$ is our only point of discontinuity.

It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at $x = 9$ (since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of $x$

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