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3 years ago

13

Find the locus of the point (x,y) which is a distance 3 from the point (-2, 1)

1 answer:

Reptile [31]3 years ago

6 0

Consider this option:
1. rule: Circle is the locus of the points which are on the same distance from the given point. Common view of the equation is: (x-a)²+(y-b)²=r², where r - the distance from the given point to the described locus, a&b - coordinates of the given point.
2. using item 1:
(x+2)²+(y-1)²=3² or (x+2)²+(y-1)²=9.

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Neporo4naja [7]

Answer:

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Step-by-step explanation:

we know that

$AD=12\ units$

$3CD=12$ ----> $CD=4\ units$

see the attached figure to better understand the problem

Triangles ABD and BCD are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

so

$\frac{BD}{AD}=\frac{CD}{BD}$

substitute the given values

$\frac{BD}{12}=\frac{4}{BD}$

$BD^2=48$

$BD=\sqrt{48}\ units$

simplify

$BD=4\sqrt{3}\ units$

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