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3 years ago

What is the probability that a randomly selected jelly bean with be a licorice jelly bean

Mathematics

2 answers:

kramer3 years ago

7 0

The probablity of licorice jelly bean being selected is 9/79

maxonik [38]3 years ago

7 0

9/79 : you have 79 overall and 9 liquorice, therefore there is a 9 in 79 chance

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3 years ago

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

algol [13]

Find the critical points of $f(x,y)$ :

$\dfrac{\partial f}{\partial x}=-2x=0\implies x=0$

$\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12$

All three points lie within $D$ , and $f$ takes on values of

$\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}$

Now check for extrema on the boundary of $D$ . Convert to polar coordinates:

$f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t$

Find the critical points of $g(t)$ :

$\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0$

$\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2$

$\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi$

where $n$ is any integer. There are some redundant critical points, so we'll just consider $0\le t< 2\pi$ , which gives

$t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3$

which gives values of

$\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}$

So altogether, $f(x,y)$ has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

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3 years ago

Find the inverse f^-1(x) if f(x)=x+2

stiks02 [169]

Answer:

f^-1(x) = x - 2

Step-by-step explanation:

To find the inverse of a function in terms of x and y, you would sway x and y in the function. We can rewrite f(x) = x + 2 as y = x + 2, since f(x) is basically y in a function. The inverse of y = x + 2 would be x = y + 2. Now, solve for y.

x = y + 2

-2 both sides.

x - 2 = y

y = x - 2

The inverse of y = x + 2 would be y = x - 2, so the inverse of f(x) = x + 2 would be f^-1(x) = x - 2 (f^-1(x) means the inverse of f(x)).

f^-1(x) = x - 2

I hope you find this helpful. :)

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