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GenaCL600 [577]
3 years ago
15

What is the gcf of 48, 64 and 72

Mathematics
2 answers:
S_A_V [24]3 years ago
6 0

The highest number that 48, 64, and 72 can all be divided by (the gcf or greatest common factor) is 8.

ziro4ka [17]3 years ago
5 0

The greatest common factor is 8 because Prime factor is 2 and 4, Number 48 is 4 and 1 Number 64 is 6 and o Number 72 is 3 and 0 which it would all equal 2^3  so 48 = 2^4 times 3 64 = 2^6 and 72 = 2^3 times 3^2 Hope this helps.

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57 divided by 8 with remainder.
zavuch27 [327]
If you would like to calculate 57 divided by 8, you can do this using the following steps:

57 divided by 8:
57 / 8 = 7 1/8 = 7.125

The correct result would be 7 1/8 or 7.125.
8 0
3 years ago
What is the lateral surface area of the pyramid?
Delicious77 [7]

Answer:

1,536 square centimeters

Step-by-step explanation:

The formula for the Lateral surface area of the pyramid =

1/2 × perimeter of the square base × slant height

Square base = 32cm

Slant height = 24cm

Perimeter of the square base = (4 × length of the square base side)

4 × 32cm = 128cm

Lateral Surface Area = 1/2 × 128cm × 24cm

= 1,536 square centimeters

6 0
3 years ago
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timofeeve [1]

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There is no answer

My Logic:

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6 0
2 years ago
10 ÷ -2<br><br> What is the quotient?
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4 0
3 years ago
Given is a finite set of spherical planets, all of the same radius and no two intersecting. On the surface of each planet consid
wariber [46]

Answer:

Step-by-step explanation:

To answer this question, First, we define a direction in space, which defines

the North Pole of each planet.

We also assume that the direction is not at 90° perpendicular to the axis of any two planet.

Assume we now define an order on the set of planet by saying that planet A ≥ B, when removing all the other planet from space, the north pole B, is visible from A.

If we refer to the direction of the planet in the diagram, we discover that,

1, A ≥ A

2, If A ≥ B and B≥ A,

Then A = B

3, If A ≥ B, and B ≥ C , then A ≥ C

4, Either A ≥ B or B ≥ A

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If we now consider a sphere of the same radius as the planets. Remove

from it all North Poles defined by directions that are perpendicular

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For every other point on this sphere, there exists a direction in

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exists a unique North Pole on one of the planets which is not visible

from the others. Hence the total area of invisible points is equal

to the area of this sphere, which in turn is the area of one of the  planets.

5 0
3 years ago
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