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cupoosta [38]
2 years ago
6

How can 26n-7m+4(10n-6m)

Mathematics
1 answer:
Olenka [21]2 years ago
3 0

Answer:

66n-31m

Step-by-step explanation:

26n-7m+4(10n-6m)

26n-7m+40n-24m

66n-31m

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3 years ago
The seventh term of an arithmetic progression is equal to twice the fifth term. The sum
mario62 [17]

Answer:

a₁ = - 24

Step-by-step explanation:

The n th term of an AP is

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where a₁ is the first term and d the common difference

Given a₇ = 2a₅ , then

a₁ + 6d = 2(a₁ + 4d) = 2a₁ + 8d ( subtract 2a₁ + 8d from both sides )

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The sum to n terms of an AP is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

Given S_{7} = 84 , then

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3.5(2a₁ + 6d) = 84 ( divide both sides by 3.5 )

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Thus we have 2 equations

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2a₁ + 6d = 24 → (2)

Multiplying (1) by 3 and adding to (2) will eliminate d

- 3a₁ - 6d = 0 → (3)

Add (2) and (3) term by term to eliminate d

- a₁ = 24 ( multiply both sides by - 1 )

a₁ = - 24

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3 years ago
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