Answer:
a) ![[-0.134,0.034]](https://tex.z-dn.net/?f=%5B-0.134%2C0.034%5D)
b) We are uncertain
c) It will change significantly
Step-by-step explanation:
a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.
Since we assume that the variances are equal, we use the pooled variance given as
,
where
.
The mean difference
.
The confidence interval is

![= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]](https://tex.z-dn.net/?f=%3D%20-0.05%5Cpm%201.995%20%5Ctimes%200.042%20%3D%20-0.05%20%5Cpm%200.084%20%3D%20%5B-0.134%2C0.034%5D)
b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.
c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.
Answer:
76 degrees
Step-by-step explanation:
this special line is an angle bisected.
that means it splits the angle at its starting point in 2 halves. as these names indicate, both parts are of equal size (half of the general angle).
we know one part (2) of this split angle : 38 degrees.
the other part (1) had to be equally sized : 38 degrees.
so, the total angle at point R is the sum of both split angles:
TRS = 38+38 = 76 degrees.
A for the first because there are 4 aces and 1 nine of hearts. that makes it 5 cards of the 52 in a deck
d for the second because there are two cards: the queen of heart and and ace of diamond out of the 52
hope this helped :)
Given:
The inequalities are:
or 
To find:
The solution for the given inequalities and graph the solution.
Solution:
We have,
or 
Solve the above inequalities separately.

Divide both sides by -5.

...(i)
And,

Divide both sides by 2.

...(ii)
From (i) and (ii). we get
or 
The interval notation of the solution is
.
The graph of the solution is shown below.