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masha68 [24]
3 years ago
7

I need 7-10 pictured

Mathematics
1 answer:
Mrac [35]3 years ago
8 0
I hope this helps you

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In the Volume of Cylinders, Cones and Spheres section, what is the volume of a sphere with a radius of 6in? *
Rudiy27

Answer:

The volume of the sphere is 288π in³

Step-by-step explanation:

To calculate the volume of a sphere we have to use the following formula:

V = volume

r = radius

V = ⁴⁄₃πr³

V = ⁴⁄₃ * π * (6in)³

V = π * ⁴⁄₃ * 216 in³

V = 288π in³

The volume of the sphere is 288π in³

4 0
3 years ago
Mark buys a treadmill priced at $360.26.Shipping and handling are an additional 10%of the price.How much shipping and handling w
Vinil7 [7]
10% of 360.26 is 36.026 but that answer wouldn’t be it since cents are only in the tenths and hundredths places after the decimal, so you’d probably have to round it up to 36.03
3 0
2 years ago
Tissues of living organisms consist primarily of organic compounds; that is, they contain carbon molecules known as proteins, ca
Marianna [84]
<span>A healthy human body is approximately 18% carbon, so to determine how many pounds of carbon a 200lb body contains, compute 200lbs X 0.18 = 36 pounds. To convert 36lbs to kilograms, multiply by the conversion factor 0.454. Therefore, 36lbs X 0.454 = 16.344 kg.</span>
6 0
3 years ago
Read 2 more answers
Find the value of a. A. 57 B. 104 C. 26 D. 52​
garik1379 [7]

Answer:

Option D, 52

Answered by GAUTHMATH

5 0
3 years ago
Please Help I will give you a lot of points if you do!
Maru [420]

Answer:

De Morgan's Theorem, T12, is a particularly powerful tool in digital design. The theorem explains that the complement of the product of all the terms is equal to the sum of the complement of each term. Likewise, the complement of the sum of all the terms is equal to the product of the complement of each term.

Step-by-step explanation:

De Morgan's Theorem, T12, is a particularly powerful tool in digital design. The theorem explains that the complement of the product of all the terms is equal to the sum of the complement of each term. Likewise, the complement of the sum of all the terms is equal to the product of the complement of each term.

4 0
3 years ago
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