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Alex777 [14]
3 years ago
14

A square has a side 9cm length . What is its area?

Mathematics
1 answer:
swat323 years ago
4 0

Answer:

81

Step-by-step explanation: A square has all sides the same so you just multiply 9×9

Have a great day and a awsome thanks giveing brake :)

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Jade buys a blouse and a skirt for 34 of their original price. She pays a total of $31.50 for the two items. If the original pri
Shtirlitz [24]

Answer:

`Part A:

D. 3/4(18 + s) = 31.50

Part B:

$36

Step-by-step explanation:

I think 34 is 3/4, is that right?

here, s is the cost of the skirt

Part A: The answer would be:

3/4(18) + 3/4(s) = 31.5 =

3/4(18 + s) = 31.5

Part B: 3/4(18) + 3/4(s) = 31.5

4.5 + 3/4s = 31.5

Subtract 4.5 from both sides:

3/4s = 27, 27 is the cost of the skirt now, but we need the original price.

multiply both sides by 4/3:

s = 36

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3 years ago
Find the quotient -7/12 divided by 1/7
leva [86]

Answer:

-4.08

Step-by-step explanation:

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3 years ago
HELP say im getting it wrong <br><br>the perimeter of the polygons is ?​
lara [203]
So the answer would be16*4=64
8 0
3 years ago
8.6 - 5.36 plz help me
olga nikolaevna [1]

Answer:

3.24

Step-by-step explanation:

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I need help with my pre-calculus homework, please show me how to solve them step by step if possible. The image of the problem i
Anna [14]

We know that the law of sines states that:

\frac{\sin\alpha}{a}=\frac{\sin\beta}{b}

For simplicity, let:

\beta=m\angle A_1BC

In triangle A1BC this leads to:

\begin{gathered} \frac{\sin31}{5}=\frac{\sin\beta}{6} \\ \sin\beta=\frac{6}{5}\sin31 \\ \beta=\sin^{-1}(\frac{6}{5}\sin31) \\ \beta=38.174 \end{gathered}

Therefore:

m\angle A_1BC=38.174

Now, triangle A2BC is isosceles which means that both the base angles are equal, since angle CA1B and A2A1B are supplementary we have:

m\angle CA_2B=180-38.174=141.826

8 0
1 year ago
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