Answer:
a circle
Step-by-step explanation:
Step-by-step explanation:
Simply Equation 1
R. H. S
6x^2 -x +3-2x^2-8
==> 6x^2-2x^2 -x +3-8
==> 4x^2-x-5 .....(1)
Simply equation 2
L. H. S
4x^2+2x-5-3x
==> 4x^2 +2x-3x-5
==> 4x^2-x-5 ....(2)
Since here, RHS = LHS
both eqn (1) = eqn(2)
hence they are equal.
The vertex is at (0, 3) so y=a(x-0)²+3, which is y=ax²+3
next, use a given point to find a: 10=a(3)²+3, so 9a=7, a=7/9
the equation is then y=

as for the first question, the shape is an ellipse, the domain is -5≤x≤5, the range is -3≤y≤3
the equation can be written as :