<h2>Hello!</h2>
The answer is: [-2,2]
<h2>
Why?</h2>
The range of a function shows where the function can exist in the y-axis.
To know the range of the function, we have to isolate x,
So
The only possible values that y can take go from -2 to 2. Taking values out of these values will give as result a non-real number.
Therefore,
The range of the function is [-2,2]
Have a nice day!
What # do you need the first five multiples for? and the only factors for 7 are one and seven because it is a prime number!
Answer:
the answer is 360. the first composite numbers are 4,6,8,9,10
and all the numbers above are divisible by 360
360÷4=90
360÷6=60
360÷8=45
360÷9=40
360÷10=36
Hello Friend,here is the solution for your question
<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)
Now here in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2) is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>
And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0 [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>
<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
=√[1/8-3(0)] [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
=√1/8
=1/(2√2)
<span>this is the maximum value now to find the minimum value </span>
<span>since this is function of root so the value of y will always be ≥0 </span>
<span>hence the minimum value of the function y is 0 </span>
<span>Therefore, the range of function </span>y is [0,1/(2√2)]
__Well,I have explained explained each and every step,do tell me if you don't understand any step._
Answer:
5000
Step-by-step explanation:
The 5 is in the "thousand" place, so it would be 5000
