The probability that a student participates in both sports and drama is
.
<h3>What is the formula for P(AUB), where A and B are any two events?</h3>
If
and
are any two events, then the probability of the joint event
is given by the following formula: ![P(A\cup B)=P(A)+P(B)-P(A\cap B)](https://tex.z-dn.net/?f=P%28A%5Ccup%20B%29%3DP%28A%29%2BP%28B%29-P%28A%5Ccap%20B%29)
Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.
Suppose
denotes that "a student participates in sports" and
denotes that "a student participates in drama".
So, we have
,
,
.
We want to find the probability that a student participates in both sports and drama i.e., we want to find
.
By the above formula, we obtain:
![P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}](https://tex.z-dn.net/?f=P%28S%5Ccup%20D%29%3DP%28S%29%2BP%28D%29-P%28S%5Ccap%20D%29%5C%5C%5CLongrightarrow%20P%28S%5Ccap%20D%29%3DP%28S%29%2BP%28D%29-P%28S%5Ccup%20D%29%5C%5C%5CLongrightarrow%20P%28S%5Ccap%20D%29%3D0.42%2B0.25-0.53%5C%5C%5Ctherefore%20P%28S%5Ccap%20D%29%3D0.14%3D%5Cfrac%7B14%7D%7B100%7D)
Therefore, the probability that a student participates in both sports and drama is
.
To learn more about probability, refer: brainly.com/question/24756209
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