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3 years ago

Three less than one-half a number is -71

Mathematics

2 answers:

morpeh [17]3 years ago

4 0

3-1/2x=-71

when you solve it, the answer is 37

Whitepunk [10]3 years ago

4 0

Since it is three less than one-half, first add 3 to -71.

-71+3=-68

Since it is one-halt this number, multiply it by 2

-68x2=-136

Hope this helps

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Rudy has been paying an annual homeowners insurance premium of $1,106.30 ($0.37 per $100 of value) since

Luden [163]

Answer:

c. $1,291.30

Step-by-step explanation:

Calculation what will his new annual homeowners insurance premium be

Insurance premium= [$1,106.30+ ($0.37/ $100*$50,000)]

Insurance premium=$1,106.30+$185

Insurance premium=$1,291.30

Therefore what his new annual homeowners insurance premium will be is $1,291.30

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3 years ago

How do you find the product of -2(3.1)

Alexxandr [17]

Answer:

- 6.2

Step-by-step explanation:

The product of - 2 (3.1) is - 6.2.

Brackets mean to multiply so we have to multiply the - 2 by 3.1 which gives a result of - 6.2.

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3 years ago

Phones-R-Us charges $16.95 per month and $0.05 per text message. Awesome Wireless charges $22.95 per

Dima020 [189]

Answer:

$S \leq 200$

Step-by-step explanation:

Given

Phone R-Us= $16.95 + $0.05 per SMS

Awesome Wireless = $22.95 + $0.02 per SMS

Required

Determine the number of SMS such that Awesome Wireless is greater or equal to Phone R-Us

Represent the SMS with S

For Phone R-Us, we have:

$SMS = 16.95 + 0.05S$

For Awesome Wireless, we have:

$SMS = 22.95 + 0.02S$

For Awesome Wireless is greater or equal to Phone R-Us, we have:

$22.95 + 0.02S \geq 16.95 + 0.05S$

Collect Like Terms

$0.02S - 0.05S \geq 16.95 - 22.95$

$-0.03S \geq -6$

Solve for S

$\frac{-0.03S}{-0.03} \geq \frac{-6}{-0.03}$

$S \leq 200$

Hence: for Awesome Wireless to cost more or equal to Phone R-Us, the number of SMS must not exceed 200

4 0

3 years ago

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$