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photoshop1234 [79]
3 years ago
14

Help me pleasee thanks

Mathematics
1 answer:
Volgvan3 years ago
6 0
The answer will be B
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Which of the following functions is not linear?
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Hi there! The answer is A.
Graph A. is not linear because it contains x^2 and therefore is a quadratic function.
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Which are the solutions of the equation x^2+4x+4=25
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I think the answer is 3,-7
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How to find the median
KengaRu [80]

<em>We </em><em>can </em><em>find </em><em>the </em><em>median </em><em>by </em><em>using </em><em>the </em><em>formula:</em>

<em>(</em><em>N+</em><em>1</em><em>/</em><em>2</em><em>)</em><em> </em><em>th </em><em>item</em>

<em>For </em><em>example:</em>

<em>Given </em><em>data:</em><em> </em><em>4</em><em>,</em><em>6</em><em>,</em><em>3</em><em>,</em><em>5</em><em>,</em><em>7</em>

<em>We </em><em>have </em><em>to </em><em>arrange </em><em>the </em><em>data </em><em>into </em><em>ascending</em><em> </em><em>order</em><em>:</em>

<em>=</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em>

<em>N(</em><em>total </em><em>no </em><em>of </em><em>items)</em><em>=</em><em>5</em>

<em>Now,</em>

<em>Median=</em><em>(</em><em>N+</em><em>1</em><em>/</em><em>2</em><em>)</em><em>th </em><em>item</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>(</em><em>5</em><em>+</em><em>1</em><em>/</em><em>2</em><em>)</em><em> </em><em>th </em><em>item</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>(</em><em>6</em><em>/</em><em>2</em><em>)</em><em> </em><em>th </em><em>item</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>3</em><em>r</em><em>d</em><em> </em><em>item</em>

<em>Median=</em><em>5</em>

<em>Hope </em><em>it</em><em> </em><em>helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

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Find the inverse of the function and then determine whether the inverse is a function.
klemol [59]

as you already know, we start off by doing a quick switcheroo on the variables, and then we solve for y to get the inverse,


\bf y=x^2+4\implies \stackrel{switcheroo}{x = y^2+4}\implies x-4=y^2\implies \pm\sqrt{x-4}=\stackrel{f^{-1}(x)}{y}


and if you run a vertical line test on that expression, you'll find that it doesn't pass it, meaning is not a function.

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An equation is shown below: 6(2x-11)+15=21
mars1129 [50]

Hello!

To solve, we want to isolate the x on one side of the equation. We can use inverse operations to put numbers on the other side to find x.

First we undistribute our parentheses.

12x-66+15=21

We subtract 15 from both sides (it cancels out the 15 on the left side, making it 0).

12x-66=6

Now we add 66 to both sides, as -66+66=0

12x=72

Finally, we divide both sides by 12.

x=6

I hope this helps!

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