Question

a triangle is graphed in the coordinate plane the vertices of the triangle have coordinates (-4, 1), (1, 1), and (1, -11). what is the perimeter of the triangle?

Answer 1

In order to calculate the perimeter of the triangle, we have to calculate the distance between the three sets of points

The distance between (-4,1) and (1,1) is calculated as follows

distance =$\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

distance =$\sqrt{(1-(-4))^2 + (1-1)^2}$

dsitance =$\sqrt{5^2 + 0}$

distance between (-4,1) and (1,1) = 5 units

The distance between (1,1) and (1,-11) is calculated as follows

distance =$\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

distance =$\sqrt{(1-1)^2 + (-11-1)^2}$

distance =$\sqrt{ 0 + 12^2}$

distance between (1,1) and (1,-11) = 12 units

The distance between (1,-11) and (-4,1) is calculated as follows

distance =$\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

distance = $\sqrt{(-4-1)^2 + (1-(-11)^2}$

distance =$\sqrt{(-5)^2 + 12^2} =\sqrt{25 + 144} = \sqrt{169}$

distance between (1,-11) and (-4,1) = 13 units

Perimeter of the trainable = 5 + 12 + 13 = 30 units

Answer 2

The triangle coordinate is -11