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Elenna [48]
3 years ago
9

A city park has 4 splash pads. Each splash pad is in the shape of a parallelogram with a base of 5.4 meters and a height of 3.8

meters. What is the total area of the splash pads?
Question 1 options:

36.8 m²

20.52 m²

82.08 m²

13.2 m²
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0
c) 82.08 m^2

Hope I helped! ( Smiles )
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A jar of 36 coins contains 9 pennies. What percent of the coins are Pennies
Luden [163]
9/36= .25


The answer is 25%
3 0
2 years ago
Read 2 more answers
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
Help me, please ;-; no links :))
pishuonlain [190]

Answer:

the answer is b good luck

8 0
2 years ago
Read 2 more answers
The park and movie theater are 3.4 inches apart on a map. If the map has a scale of 0.25 inch = 5 miles, find the actual distanc
lianna [129]

The actual distance between park and movie theater is 68 miles, if the park and movie theater are 3.4 inches apart on a map and the map has a scale of 0.25 inch = 5 miles.

Step-by-step explanation:

The given is,

             Park and movie theater are 3.4 inches apart

             Map has a scale of 0.25 inch = 5 miles

Step:1

            Formula to calculate the number of scales for distance between park and theater,

                                        = \frac{Distance in map}{Scale value of map}

                                        = \frac{3.4}{0.25}

                                        = 13.6

            number of scales for distance between park and theater  = 13.6

Step:2

            Formula to convert distance inches to miles

                                      = Number of scale × Equivalent value inches to miles

                                      = 13.6 × 5

                                      = 68

            Actual distance between park and theater = 68 miles

Result:

           The actual distance between park and movie theater is 68 miles, if the park and movie theater are 3.4 inches apart on a map and the map has a scale of 0.25 inch = 5 miles.

6 0
3 years ago
Can anyone help me with this question please ? <br> I’ll mark you as a brainliest
DanielleElmas [232]
B is the answer i beleive
4 0
3 years ago
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